Which conditions can cause hypovolemic shock? Select all that apply.

Diarrhea

Vomiting

Lower GI bleed

Tension pneumothorax

Diabetes insipidus

Valvular stenosis

Answer and Explanation

Correct Answer : A,B,C,D

These conditions can lead to fluid loss, either through increased gastrointestinal output (diarrhea, vomiting, lower GI bleeding) or accumulation of air in the pleural space (tension pneumothorax), resulting in a decrease in blood volume and subsequent hypovolemic shock.
E. Diabetes insipidus in (option E) is incorrect because it is not directly associated with hypovolemic shock. Diabetes insipidus is a condition characterized by excessive thirst and the production of large volumes of dilute urine due to insufficient production or response to antidiuretic hormone (ADH). While diabetes insipidus can lead to dehydration and potential hypovolemia, it is not a direct cause of hypovolemic shock.
F. Valvular stenosis in (option F) is incorrect because it is a condition characterized by the narrowing or obstruction of one or more heart valves. While it can cause problems with cardiac output and circulation, it is not specifically related to hypovolemic shock, which is caused by a decrease in blood volume.
Therefore, the conditions that can cause hypovolemic shock include diarrhea, vomiting, lower GI bleeding, and tension pneumothorax.

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Correct Answer is C

Explanation

This method, known as the 6-second method, involves counting the number of QRS complexes in a 6-second interval on the electrocardiogram (ECG) strip and then multiplying that number by 10 to calculate the heart rate per minute. The advantage of this method is that it provides a relatively quick estimate of the heart rate.
A. Printing a 1-minute ECG strip and counting the number of QRS complexes in (option A) is incorrect because it can be time-consuming and may not be practical in situations where a quick estimate is needed.
B. Calculating the number of small squares between one QRS complex and the next and dividing into 1500 in (option B) is incorrect because it is a method used to calculate heart rate, known as the "1500 method," but it is not as quick as the 6-second method and requires more time and measurement precision.
D. Counting the number of large squares in the R-R interval and dividing by 300 is another method used to calculate heart rate, known as the "300 method," but it is also less quick and less accurate for assessing heart rate in patients with regular rhythms.
It's important to note that if the heart rhythm is irregular, these methods may not provide an accurate estimate of the heart rate, and a longer monitoring period or a different approach may be necessary.

A. 18 Ml B. 5480 Ml C. 6,480 mL D. 4234 mL

Correct Answer is C

Explanation

Heart rate: 72 beats per minute Stroke volume: 90 mL/contraction

Cardiac output = Heart rate × Stroke volume

Cardiac output = 72 beats/minute × 90 mL/contraction

To simplify the calculation, you can convert the units:

72 beats/minute × 90 mL/contraction = (72 × 90) beats/minute × mL/contraction

Now, perform the multiplication:

72 × 90 = 6,480

Therefore, the cardiac output is 6,480 mL per minute.

The correct answer is:

C. 6,480 mL

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Which conditions can cause hypovolemic shock? Select all that apply.

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Naxlex Comprehensive Predictor Exams

The nurse needs to estimate quickly the heart rate of a patient with a regular heart rhythm. Which method will be best to use?

Correct Answer is C

Explanation

What is the cardiac output of a patient whose heart rate is 72 beats per minute with a stroke volume of 90 mL/contraction?

Correct Answer is C

Explanation

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