Which of the following clinical manifestations of Disseminated intravascular coagulation (DIC)?
Decreased hematocrit, increased platelet counts, increased D-dimer
Decreased platelet counts, increased D-dimer, increased prothrombin time
Decreased Antithrombin III, increased platelet counts, increased fibrinogen
Decreased D-dimer, increased platelet counts, Increased hemoglobin
The Correct Answer is B
Disseminated Intravascular Coagulation (DIC) is a condition characterized by widespread activation of the coagulation system, leading to both excessive clot formation and consumption of clotting factors and platelets. This process can result in both bleeding and thrombosis.
The manifestations mentioned in option B are commonly seen in DIC:
Decreased platelet counts: DIC leads to platelet consumption and destruction, resulting in low platelet counts (thrombocytopenia).
Increased D-dimer: D-dimer is a fibrin degradation product, and its levels are increased DIC due to the breakdown of fibrin clots.
Increased prothrombin time (PT): DIC can lead to the depletion of clotting factors, resulting in prolonged prothrombin time, indicating impaired coagulation.
The other options mentioned do not represent the typical clinical manifestations of DIC:
A. Decreased hematocrit, increased platelet counts, and increased D-dimer in (option A) are incorrect because While platelet counts and D-dimer are increased in DIC, decreased hematocrit is not a characteristic finding.
C. Decreased Antithrombin III, increased platelet counts, and increased fibrinogen in (option C) is incorrect because: Decreased Antithrombin III can be seen in DIC, but increased platelet counts and fibrinogen levels are not specific to DIC.
D. Decreased D-dimer, increased platelet counts, and increased hemoglobin in (option D) is incorrect because Decreased D-dimer and increased hemoglobin are not typical findings in DIC, while increased platelet counts can be seen in some cases.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is ["A","B","D","E"]
Explanation
A. Narrowed pulse pressure: In cardiogenic shock, the cardiac output is compromised, resulting in reduced stroke volume and subsequent narrowed pulse pressure. The pulse pressure is the difference between systolic and diastolic blood pressure.
B. Tachycardia: Tachycardia is a compensatory response in cardiogenic shock, as the body attempts to increase cardiac output to maintain tissue perfusion despite decreased stroke volume. Increased heart rate is a common finding in this condition.
D. Pulmonary congestion: Cardiogenic shock is often associated with impaired left ventricular function, leading to an inadequate pump mechanism. This can result in fluid accumulation and congestion in the pulmonary circulation, leading to pulmonary edema and congestion. Patients may experience symptoms such as dyspnea, crackles on lung auscultation, and increased work of breathing.
E. Elevated pulmonary artery wedge pressure (PAWP): PAWP is a measurement obtained during invasive hemodynamic monitoring. In cardiogenic shock, the impaired left ventricular function leads to increased left atrial pressure, which is reflected by an elevated PAWP. Elevated PAWP indicates increased fluid volume and congestion in the left side of the heart.
C. Elevated SBP in (option C) is incorrect because Elevated systolic blood pressure (SBP) is not a typical finding in cardiogenic shock. Instead, hypotension or decreased blood pressure is commonly observed due to reduced cardiac output.
Correct Answer is ["9"]
Explanation
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Doseinmcg/min=2mcg/kg/min×60kg=120mcg/min
Convert this to mg/min since the concentration is in mg:
120mcg/min=0.12mg/min120 \text{ mcg/min} = 0.12 \text{ mg/min}120mcg/min=0.12mg/min
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Determine the concentration of Dopamine:
- Total amount of Dopamine: 200 mg in 250 mL of saline
- Concentration:
Concentration=200mg250mL=0.8mg/mL\text{Concentration} = \frac{200 \text{ mg}}{250 \text{ mL}} = 0.8 \text{ mg/mL}Concentration=250mL200mg=0.8mg/mL
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Calculate the pump rate in mL/min:
To find the rate in mL/min needed to deliver 0.12 mg/min:
Pumprate=Desireddose(mg/min)Concentration(mg/mL)\text{Pump rate} = \frac{\text{Desired dose (mg/min)}}{\text{Concentration (mg/mL)}}Pumprate=Concentration(mg/mL)Desireddose(mg/min)
Pumprate=0.12mg/min0.8mg/mL=0.15mL/min\text{Pump rate} = \frac{0.12 \text{ mg/min}}{0.8 \text{ mg/mL}} = 0.15 \text{ mL/min}Pumprate=0.8mg/mL0.12mg/min=0.15mL/min
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Convert the pump rate to mL/hour:
Multiply by 60 to convert from mL/min to mL/hour:
Pumprate=0.15mL/min×60min/hour=9mL/hour\text{Pump rate} = 0.15 \text{ mL/min} \times 60 \text{ min/hour} = 9 \text{ mL/hour}Pumprate=0.15mL/min×60min/hour=9mL/hour
So, you should set the pump to deliver Dopamine at a rate of 9 mL/hour.
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