The practical nurse (PN) is assisting with the plan of care for a client who is experiencing torticollis from a traumatic injury sustained during a football game. The client received a prescription for tramadol. Which intervention should the PN include in the client's plan of care?
Encourage the client to resume normal activities after medication administration.
Observe the client for involuntary movements of the lips and tongue every day.
Perform a daily whisper test of the client's hearing to detect symptoms of ototoxicity.
Implement ongoing assessments for signs of shallow or slow breathing.
The Correct Answer is D
Tramadol is an opioid analgesic that can depress the respiratory system and potentially cause respiratory depression. Therefore, it is crucial for the PN to closely monitor the client's breathing pattern, depth, and rate. Assessing for signs of shallow or slow breathing is important to detect any potential respiratory depression and take appropriate action promptly.
The other options listed are not directly related to the administration of tramadol:
A. Encouraging the client to resume normal activities after medication administration is not an appropriate intervention for a client experiencing torticollis. The focus should be on pain management, rest, and implementing measures to relieve the torticollis.
B. Observing the client for involuntary movements of the lips and tongue every day is not specifically related to tramadol. This intervention is more relevant to monitoring for tardive dyskinesia, a side effect associated with certain antipsychotic medications.
C. Performing a daily whisper test of the client's hearing to detect symptoms of ototoxicity is not necessary with tramadol. Ototoxicity refers to damage to the inner ear, often caused by specific medications, but tramadol is not known to cause ototoxic effects.
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Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
The client is prescribed oxygen at 3 liters per minute, but the flowmeter shows that only 1 liter of oxygen is being delivered. This indicates an inadequate oxygen supply and immediate action is required to adjust the flow rate to meet the prescribed oxygen requirement. Failure to provide the appropriate oxygen flow rate can compromise the client's respiratory status and oxygenation. The PN should promptly increase the flow rate to the prescribed level to ensure the client receives the necessary oxygen therapy.
The other assessment findings mentioned are also important to note and address, but they do not require immediate action:
A. The client lying in a supine position in bed: While it is generally recommended for clients receiving oxygen therapy to be in an upright or semi-upright position, this finding does not require immediate action unless there are specific indications or contraindications related to the client's condition.
B. The cannula pressed snugly against the client's cheeks: The cannula should fit comfortably and securely on the client's face without causing discomfort or pressure areas. While this finding may require adjustment to ensure proper fit and comfort, it does not require immediate action unless it is causing harm or compromising oxygen delivery.
D. There is no humidifier attached to the delivery system: While a humidifier may be recommended to add moisture to the oxygen, its absence does not pose an immediate threat to the client's safety or require immediate action. The need for humidification depends on the client's condition and comfort level, and it can be addressed by attaching a humidifier if necessary.
Correct Answer is ["0.6"]
Explanation
To calculate how many milliliters (mL) the practical nurse (PN) should administer each day, we can first determine the total daily dosage of enoxaparin.
The prescribed dosage is 30 mg every 12 hours, so the total daily dosage is:
30 mg + 30 mg = 60 mg
Next, we can calculate the number of milliliters (mL) needed to deliver the total daily dosage. Since the medication is available in a concentration of 30 mg per 0.3 mL, we can set up a proportion to find the equivalent mL for 60 mg:
30 mg / 0.3 mL = 60 mg / x mL
Cross-multiplying, we get:
30 mg * x mL = 60 mg * 0.3 mL
30x = 18
Dividing both sides by 30, we find:
x = 0.6 mL
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