The nurse places an opioid patch on the chest of a client with intractable pain who also has obstructive sleep apnea (OSA). Which intervention is most important for the nurse to implement before leaving the client?
Remove dentures or other oral appliances.
Lift and lock the side rails in place.
Apply the client's positive airway pressure device.
Elevate the head of the bed to a 45-degree angle.
The Correct Answer is C
Choice A reason: Removing dentures or other oral appliances may be necessary for some medical procedures, but it is not the most important intervention for a client with OSA who has just received an opioid patch.
Choice B reason: Lifting and locking the side rails in place is a standard safety measure, but it does not directly address the respiratory concerns associated with OSA and opioid use.
Choice C reason: Applying the client's positive airway pressure device is the most important intervention. Opioids can depress respiration, and for a client with OSA, ensuring the airway is patent and supported by a positive airway pressure device is crucial to prevent respiratory complications.
Choice D reason: Elevating the head of the bed can aid in respiration, but it is not as immediately critical as ensuring the use of a positive airway pressure device for a client with OSA who is receiving opioids.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
Choice A reason: While pneumatic compression devices are used for DVT prevention, they are not the immediate intervention for suspected stroke.
Choice B reason: Placing an indwelling urinary catheter is not the first-line intervention for a patient with suspected stroke symptoms.
Choice C reason: Notifying the stroke team is the most appropriate action as the patient's symptoms suggest a possible stroke, requiring urgent evaluation and management.
Choice D reason: Aspirin may be used in the management of stroke, but only after a stroke has been confirmed and not as an immediate intervention.
Correct Answer is ["2"]
Explanation
Step 1: We need to find out how many mL contain 10 mg of loratadine. Since 5 mg of loratadine is in 5 mL, we can set up a proportion to find out how many mL contain 10 mg.
So, 5 mg is to 5 mL as 10 mg is to X mL.
This gives us the equation: (5 mg ÷ 5 mL) = (10 mg ÷ X mL)
Step 2: Solving for X gives us X = (10 mg × 5 mL) ÷ 5 mg
Step 3: Simplifying gives us X = 10 mL
So, the client needs to take 10 mL of the loratadine suspension to get a dose of 10 mg.
Now, we need to convert this volume in mL to teaspoons, using the conversion factor you provided (1 teaspoon = 5 mL).
Step 4: We set up the conversion as follows: 10 mL × (1 tsp ÷ 5 mL)
Step 5: Simplifying gives us 2 tsp
So, the nurse should instruct the client to take 2 teaspoons of the loratadine suspension.
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