Four hours after mechanical ventilation is initiated for a patient with a suspected drug overdose, the patient's arterial blood gas (ABG) results include a pH of 7.50, Pa0 2 of 80 mm Hg. PaCO2 of 29 mmHg, and HCO3 of 23 mEq/L (23 mmo/L). The nurse will anticipate the need to:
decrease the respiratory rate.
Leave the ventilator at the current settings.
increase the tidal volume (VT).
Increase the F102
The Correct Answer is A
The ABG results show a pH of 7.50, PaCO2 of 29 mmHg, and HCO3 of 23 mEq/L, indicating respiratory alkalosis. In respiratory alkalosis, there is a decrease in PaCO2 (hypocapnia), which can be caused by excessive ventilation.
To address the respiratory alkalosis, the nurse should decrease the respiratory rate. This would help reduce the amount of ventilation provided and allow the patient to retain more carbon dioxide (CO2), thereby increasing the PaCO2 levels and restoring acid-base balance.
B. Leaving the ventilator at the current settings in (option B) is incorrect because it may exacerbate respiratory alkalosis as it would maintain the same level of ventilation.
C. Increasing the tidal volume (VT) in (option C) is incorrect because it would not address the respiratory alkalosis. Tidal volume refers to the volume of air delivered with each breath, while the issue in this case is excessive ventilation leading to hypocapnia.
D. Increasing the FiO2 (fraction of inspired oxygen) in (option D) is incorrect because it is not indicated based on the given ABG results. The oxygenation (PaO2) level is within normal limits (80 mmHg), suggesting adequate oxygenation.
It is important to consult with the healthcare provider or respiratory therapist for further guidance on adjusting the ventilator settings based on the patient's condition and response to therapy.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is ["9000"]
Explanation
4 mL × body weight in kg × percentage of burn = total fluid volume for the first 24 hours Then, divide the total fluid volume by 2 to determine the fluid volume for the first 8 hours.
In this case, the patient weighs 90 kg and has a 50% burn injury.
4 mL × 90 kg × 50% = 18,000 mL (total fluid volume for 24 hours)
18,000 mL / 2 = 9,000 mL (fluid volume for the first 8 hours)
Therefore, the nurse would infuse the intravenous fluid resuscitation at a rate of 9,000 mL over the first 8 hours.
Correct Answer is ["A","B","D","E"]
Explanation
A. Narrowed pulse pressure: In cardiogenic shock, the cardiac output is compromised, resulting in reduced stroke volume and subsequent narrowed pulse pressure. The pulse pressure is the difference between systolic and diastolic blood pressure.
B. Tachycardia: Tachycardia is a compensatory response in cardiogenic shock, as the body attempts to increase cardiac output to maintain tissue perfusion despite decreased stroke volume. Increased heart rate is a common finding in this condition.
D. Pulmonary congestion: Cardiogenic shock is often associated with impaired left ventricular function, leading to an inadequate pump mechanism. This can result in fluid accumulation and congestion in the pulmonary circulation, leading to pulmonary edema and congestion. Patients may experience symptoms such as dyspnea, crackles on lung auscultation, and increased work of breathing.
E. Elevated pulmonary artery wedge pressure (PAWP): PAWP is a measurement obtained during invasive hemodynamic monitoring. In cardiogenic shock, the impaired left ventricular function leads to increased left atrial pressure, which is reflected by an elevated PAWP. Elevated PAWP indicates increased fluid volume and congestion in the left side of the heart.
C. Elevated SBP in (option C) is incorrect because Elevated systolic blood pressure (SBP) is not a typical finding in cardiogenic shock. Instead, hypotension or decreased blood pressure is commonly observed due to reduced cardiac output.

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