Four hours after mechanical ventilation is initiated for a patient with a suspected drug overdose, the patient's arterial blood gas (ABG) results include a pH of 7.50, Pa0 2 of 80 mm Hg. PaCO2 of 29 mmHg, and HCO3 of 23 mEq/L (23 mmo/L). The nurse will anticipate the need to:
decrease the respiratory rate.
Leave the ventilator at the current settings.
increase the tidal volume (VT).
Increase the F102
The Correct Answer is A
The ABG results show a pH of 7.50, PaCO2 of 29 mmHg, and HCO3 of 23 mEq/L, indicating respiratory alkalosis. In respiratory alkalosis, there is a decrease in PaCO2 (hypocapnia), which can be caused by excessive ventilation.
To address the respiratory alkalosis, the nurse should decrease the respiratory rate. This would help reduce the amount of ventilation provided and allow the patient to retain more carbon dioxide (CO2), thereby increasing the PaCO2 levels and restoring acid-base balance.
B. Leaving the ventilator at the current settings in (option B) is incorrect because it may exacerbate respiratory alkalosis as it would maintain the same level of ventilation.
C. Increasing the tidal volume (VT) in (option C) is incorrect because it would not address the respiratory alkalosis. Tidal volume refers to the volume of air delivered with each breath, while the issue in this case is excessive ventilation leading to hypocapnia.
D. Increasing the FiO2 (fraction of inspired oxygen) in (option D) is incorrect because it is not indicated based on the given ABG results. The oxygenation (PaO2) level is within normal limits (80 mmHg), suggesting adequate oxygenation.
It is important to consult with the healthcare provider or respiratory therapist for further guidance on adjusting the ventilator settings based on the patient's condition and response to therapy.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is D
Explanation
In the compensatory stage of shock, the body initiates various mechanisms to maintain perfusion to vital organs and restore homeostasis. Activation of the renin-angiotensin system is one of the compensatory responses. The decreased blood flow and oxygen delivery to the kidneys stimulate the release of renin from the kidneys. Renin acts on angiotensinogen, converting it into angiotensin I, which is further converted to angiotensin II by the action of angiotensin-converting enzyme (ACE). Angiotensin II is a potent vasoconstrictor and also stimulates the release of aldosterone, leading to sodium and water retention. These mechanisms aim to increase blood pressure and cardiac output and restore fluid balance.
A. The initial stage of shock in (option A) is incorrect because it is characterized by inadequate tissue perfusion and the activation of various compensatory mechanisms, including the release of stress hormones. However, the renin-angiotensin system is not specifically mentioned as activated in this stage.
B. The progressive stage of shock in (option B) is incorrect because it occurs when compensatory mechanisms fail to maintain adequate perfusion, leading to worsening hypoperfusion and organ dysfunction. The renin-angiotensin system continues to be activated during this stage, but it is primarily associated with the compensatory stage.
C. The refractory stage of shock in (option C) is incorrect because it is the stage of severe and prolonged hypoperfusion, where organ failure becomes irreversible. The renin-angiotensin system may still be activated, but it is not the primary focus of this stage.
Therefore, the activation of the renin-angiotensin system occurs during the compensatory stage of shock.

Correct Answer is C
Explanation
Heart rate: 72 beats per minute Stroke volume: 90 mL/contraction
Cardiac output = Heart rate × Stroke volume
Cardiac output = 72 beats/minute × 90 mL/contraction
To simplify the calculation, you can convert the units:
72 beats/minute × 90 mL/contraction = (72 × 90) beats/minute × mL/contraction
Now, perform the multiplication:
72 × 90 = 6,480
Therefore, the cardiac output is 6,480 mL per minute.
The correct answer is:
C. 6,480 mL
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