A pregnant woman experiencing nausea and vomiting should:.
Drink a glass of water with a fat-free carbohydrate before getting out of bed in the morning.
Eat small, frequent meals (every 2 to 3 hours).
Increase her intake of high-fat foods to keep the stomach full and coated.
Limit fluid intake throughout the day.
The Correct Answer is B
Choice A rationale:
Drink a glass of water with a fat-free carbohydrate before getting out of bed in the morning. While staying hydrated is important, consuming a fat-free carbohydrate before getting out of bed may not be sufficient to alleviate nausea and vomiting. Eating small, frequent meals throughout the day, as suggested in choice B, can help stabilize blood sugar levels and prevent the stomach from becoming too empty, which can contribute to nausea.
Choice B rationale:
Eat small, frequent meals (every 2 to 3 hours). Eating small, frequent meals can help manage nausea and vomiting during pregnancy. Having something in the stomach at all times can prevent the stomach from becoming completely empty, reducing the likelihood of nausea. Additionally, choosing easily digestible foods can further alleviate symptoms.
Choice C rationale:
Increase her intake of high-fat foods to keep the stomach full and coated. Increasing intake of high-fat foods is not advisable, as they can be harder to digest and may exacerbate nausea. The focus should be on consuming small, low-fat, easily digestible meals throughout the day.
Choice D rationale:
Limit fluid intake throughout the day. Limiting fluid intake is not recommended, especially during pregnancy. It's important for pregnant women to stay hydrated. Dehydration can worsen nausea and may lead to other complications. Encouraging adequate fluid intake between meals can also help manage nausea.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is B
Explanation
Choice A rationale:
Koplik's spots are small white or bluish-white spots with a red halo that appear inside the mouth on the buccal mucosa. They are a characteristic sign of measles (rubeola). Measles is a highly contagious viral infection characterized by fever, cough, runny nose, and a distinctive red rash. The presence of Koplik's spots is a specific diagnostic feature of measles, making choice A incorrect for this scenario.
Choice B rationale:
Koplik's spots are a classic sign of measles (rubeola). These spots typically appear a few days before the onset of the measles rash and are highly indicative of the disease. Measles is a highly contagious viral infection that spreads through respiratory droplets. It is essential to recognize Koplik's spots as they provide an early clue to the diagnosis of measles, enabling healthcare providers to take appropriate precautions and prevent the further spread of the disease.
Choice C rationale:
Chickenpox (varicella) presents with an itchy rash that progresses to fluid-filled blisters. However, Koplik's spots are not associated with chickenpox. Chickenpox is caused by the varicella-zoster virus and is characterized by a widespread rash, fever, and general discomfort. Koplik's spots are specific to measles and do not occur in chickenpox.
Choice D rationale:
Exanthema subitum, also known as roseola, is a viral illness that primarily affects infants and young children. It is characterized by high fever followed by a rash. However, Koplik's spots are not a feature of roseola. The rash in roseola appears after the fever subsides and is typically pink or red, differentiating it from the small white spots seen in measles.
Correct Answer is C
Explanation
Choice A rationale:
Rh incompatibility occurs when an Rh-negative mother is exposed to Rh-positive fetal blood, leading to the development of antibodies against Rh-positive blood cells. In this scenario, the infant of an Rh-negative mother and an Rh-positive father who is heterozygous for the Rh factor (Choice C) is more likely to have Rh incompatibility. This is because there is a higher chance that the fetus will be Rh-positive, and the mother, being Rh-negative, may produce antibodies against the Rh-positive cells of the baby, causing hemolytic disease of the newborn.
Choice B rationale:
If both the mother and the infant are Rh-negative (Choice B), there is no Rh incompatibility, as there is no Rh-positive blood to trigger an immune response in the mother.
Choice D rationale:
If both the mother and the infant are Rh-positive (Choice D), there is also no Rh incompatibility, as there is no Rh-negative blood to cause an immune reaction in the mother.
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