A 29-year-old female patient is admitted to the emergency department with two of the systemic inflammatory response syndrome variables: temperature of 101.2 °F and 14,000 per μL white blood cell count. Which intervention from the sepsis resuscitation bundle does the nurse initiate?
Cooling baths
Broad-spectrum antibiotics
Blood transfusion
NPO status
The Correct Answer is B
The patient's symptoms of fever and elevated white blood cell count suggest a potential infection and sepsis. Broad-spectrum antibiotics should be initiated promptly to cover a wide range of possible pathogens until further diagnostic tests and identification of the specific causative agent are obtained. Early administration of appropriate antibiotics is crucial in sepsis management to target the suspected infection and improve patient outcomes.
A. Cooling baths in (option A) is incorrect because: Cooling baths are typically used in the management of hyperthermia or specific conditions like heatstroke. While the patient has an elevated temperature, it is likely due to the systemic inflammatory response rather than solely hyperthermia.
C. Blood transfusion in (option C) is incorrect because Blood transfusion may be required in certain cases of sepsis if there is evidence of significant anemia or active bleeding. However, based on the information provided, there is no immediate indication of a blood transfusion.
D. NPO status in (option D) is incorrect because NPO status (nothing by mouth) is a general precautionary measure used in various situations, such as prior to surgery or to manage gastrointestinal complications. It is not a specific intervention in the sepsis resuscitation bundle.
Therefore, the nurse should initiate the intervention of administering broad-spectrum antibiotics in this scenario.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
This method, known as the 6-second method, involves counting the number of QRS complexes in a 6-second interval on the electrocardiogram (ECG) strip and then multiplying that number by 10 to calculate the heart rate per minute. The advantage of this method is that it provides a relatively quick estimate of the heart rate.
A. Printing a 1-minute ECG strip and counting the number of QRS complexes in (option A) is incorrect because it can be time-consuming and may not be practical in situations where a quick estimate is needed.
B. Calculating the number of small squares between one QRS complex and the next and dividing into 1500 in (option B) is incorrect because it is a method used to calculate heart rate, known as the "1500 method," but it is not as quick as the 6-second method and requires more time and measurement precision.
D. Counting the number of large squares in the R-R interval and dividing by 300 is another method used to calculate heart rate, known as the "300 method," but it is also less quick and less accurate for assessing heart rate in patients with regular rhythms.
It's important to note that if the heart rhythm is irregular, these methods may not provide an accurate estimate of the heart rate, and a longer monitoring period or a different approach may be necessary.
Correct Answer is A
Explanation
Tachypnoea, which refers to an increased respiratory rate, is an early symptom of hypovolemic shock. It is the body's compensatory response to inadequate tissue perfusion and decreased oxygen delivery. The increased respiratory rate is an attempt to improve oxygenation and maintain vital organ function.
B. Heart blocks in (option B) are incorrect because Heart blocks refer to disruptions in the electrical conduction system of the heart and are not specific to hypovolemic shock.
C. Vomiting in (option C) is incorrect because: Vomiting may occur in various conditions, including shock, but it is not exclusive to hypovolemic shock and can be present in other forms of shock or illnesses.
D. Bradycardia in (option D) is incorrect because Bradycardia, or a slow heart rate, is not typically an early symptom of hypovolemic shock. Instead, tachycardia (rapid heart rate) is more commonly observed as a compensatory response to maintain cardiac output.
E. Hypotension in (option E) is incorrect because Hypotension, or low blood pressure, can occur in hypovolemic shock but is generally considered a later-stage symptom. In the early stages, compensatory mechanisms may help maintain blood pressure, so hypotension may not be present initially.
F. Bradypnea in (option F) is incorrect because: Bradypnea refers to a slow respiratory rate, which is not typically an early symptom of hypovolemic shock. Tachypnoea, as mentioned earlier, is the more common early respiratory symptom.
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