The practical nurse (PN) is preparing cefazolin 400 mg IM for a client with a gram-positive infection. The available vial is labeled, "Cefazolin 1 gram," and the instructions for reconstitution state, for IM use, add 2 mL sterile water for injection. Total volume after reconstitution is 2.5 mL. After reconstitution, how many mL should be administered to the client? (Enter numeric value only. If rounding is required, round to the whole number, nearest tenths/hundredth).
The Correct Answer is ["1"]
This is the correct answer because the concentration of cefazolin after reconstitution is 1 gram/2.5 mL, which is equivalent to 400 mg/1 mL. Therefore, to administer 400 mg of cefazolin, the PN should draw up 1 mL of the reconstituted solution. This can be calculated using the formula:
Desired dose / Available dose = Volume to administer
400 mg / 1000 mg = x mL / 2.5 mL
x = (400 x 2.5) / 1000
x = 1 mL

Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is D
Explanation
Choice A rationale:
Systemic autoimmune vasculopathy is not a typical underlying disease pathology associated with a waddling gait and frequent falls in a 5-year-old child. This choice is not relevant to the symptoms described.
Choice B rationale:
Autonomic neuropathy may manifest with a variety of symptoms, including autonomic dysregulation, but it is not a common underlying pathology leading to a waddling gait and frequent falls in a child. This choice is not relevant to the symptoms described.
Choice C rationale:
Impaired neuron function can result in various neurological symptoms, but it does not specifically explain the waddling gait and frequent falls in a 5-year-old child. This choice is not relevant to the symptoms described.
Choice D rationale:
Correct Answer is {"dropdown-group-1":"A","dropdown-group-2":"D"}
Explanation
Choice A rationale:
A pH level of 7.35 to 7.45 and HCO3- level of 22 to 26 mEq/L indicate a resolution of ketoacidosis. The normal pH range for the body is 7.35 to 7.45, and a return to this range indicates that the body’s acid-base balance has been restored. The bicarbonate (HCO3-) level is a measure of the metabolic component of the body’s acid-base balance, and the normal range is 22 to 26 mEq/L. A return to this range indicates that the metabolic acidosis caused by the ketoacidosis has been resolved.
Choice B rationale:
A pH level of 7.25 to 7.35 and HCO3- level of 18 to 22 mEq/L would indicate that the client is still in a state of mild acidosis, as the pH is below the normal range and the bicarbonate level is also slightly low, indicating a metabolic acidosis.
Choice C rationale:
A pH level of 7.15 to 7.25 and HCO3- level of 14 to 18 mEq/L would indicate a moderate acidosis. Both the pH and bicarbonate levels are significantly below their normal ranges, indicating a significant disruption in the body’s acid-base balance.
Choice D rationale:
A pH level of 7.05 to 7.15 and HCO3- level of 10 to 14 mEq/L would indicate severe acidosis, which would be life-threatening if not corrected. Both the pH and bicarbonate levels are far below their normal ranges, indicating a severe disruption in the body’s acid-base balance. In conclusion, choice A is correct because it represents values within the normal ranges for both pH and bicarbonate, indicating a resolution of ketoacidosis.
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