The nurse is visiting a new mother who has been home with a new infant for 4 days. Which observation indicates that the mother's home environment was inadequately assessed prior to being discharged from the hospital?
The baby sleeps with the mother in bed.
The windows are covered with screens.
The kitchen has a refrigerator.
The baby has a changing area.
The Correct Answer is A
The baby sleeps with the mother in bed. This is because sleeping with the baby in the same bed increases the risk of sudden infant death syndrome (SIDS), suffocation, strangulation, and entrapment. The nurse should have assessed the mother’s sleeping arrangements for the baby and provided education on safe sleep practices before discharge. The nurse should advise the mother to place the baby on a firm surface, such as a crib or bassinet, in the same room but not in the same bed as the mother.
Choice B is wrong because having windows covered with screens is not a sign of inadequate home assessment. Screens can help prevent insects and other animals from entering the home and posing a health hazard.
Choice C is wrong because having a refrigerator in the kitchen is not a sign of inadequate home assessment. A refrigerator can help store food and breast milk safely and prevent spoilage and contamination.
Choice D is wrong because having a changing area for the baby is not a sign of inadequate home assessment. A changing area can help keep the baby clean and comfortable and prevent diaper rash and infection.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is A
Explanation
Asymmetrical chest movement is a sign of respiratory distress in the newborn, as it indicates unequal lung expansion or airway obstruction. A respiratory rate of 50 breaths/minute (choice B) is normal for a newborn, as is acrocyanosis (choice C), which is a bluish discoloration of the hands and feet due to immature peripheral circulation. Short periods of apnea (less than 15 seconds) (choice D) are also common and benign in newborns unless they are associated with bradycardia or cyanosis.
Choice B is not correct because a respiratory rate of 50 breaths/minute is within the normal range for a newborn.
Choice C is not correct because acrocyanosis is a normal finding in newborns and does not indicate respiratory distress.
Choice D is not correct because short periods of apnea (less than 15 seconds) are normal in newborns and do not indicate respiratory distress.
Correct Answer is D
Explanation
Wash hands before touching each baby. This is because hand hygiene is the most effective way to prevent infection transmission in the nursery. Hand hygiene should be performed before and after every patient contact, as well as before and after wearing gloves or handling equipment. Hand hygiene can be done by washing hands with soap and water or using alcohol-based hand rubs.
Choice A is not correct because adjusting room temperature between 75°F and 80°F is not a measure to protect newborns from infection. The room temperature should be maintained within a comfortable range for newborns, but it does not affect infection risk.
Choice B is not correct because wearing a disposable gown when giving infant care is not a measure to protect newborns from infection. Disposable gowns are part of contact precautions, which are used for patients with known or suspected infections that can be transmitted by direct or indirect contact. They are not necessary for routine infant care.
Choice C is not correct because keeping the newborn dressed warmly is not a measure to protect newborns from infection. Keeping the newborn dressed warmly can help prevent heat loss and hypothermia, but it does not affect infection risk.
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