A nurse is caring for a client who is 4 hr postpartum. The nurse finds a small amount of lochia rubra on the client's perineal pad. The fundus is midline and firm at the umbilicus. Which of the following actions should the nurse take?
Increase the rate of IV fluids.
Assist the client to ambulate.
Perform fundal massage.
Check for blood under the client's buttock.
The Correct Answer is D
Check for blood under the client's buttock. This is because lochia rubra is the normal vaginal discharge that occurs after childbirth, consisting of blood, mucus, and tissue from the placenta and the uterus lining. It is usually heavy for the first three to four days and can pool under the client's buttocks if they are lying down. Checking for blood under the buttock can help assess the amount of bleeding and prevent complications such as infection or hemorrhage.
The other choices are not correct for the following reasons:
A. Increasing the rate of the IV fluids is not necessary because the client's fundus is firm and midline, indicating that the uterus is contracting well and preventing excessive bleeding.
B. Assisting the client to ambulate is not advisable because it can increase the lochia flow and cause fainting or dizziness due to blood loss.
C. Performing fundal massage is not indicated because the fundus is already firm and midline, meaning that the uterus is adequately contracted. Massaging a firm fundus can cause pain and discomfort to the client.
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Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is A
Explanation
Endometritis. This is because the client's symptoms suggest that she has endometritis, which is an infection of the lining of the uterus. Endometritis is a common postpartum complication that can occur after vaginal or cesarean delivery. The client may also have foul-smelling vaginal discharge, chills, and fatigue.
Choice B is wrong because cystitis is an infection of the bladder that causes pain or burning during urination, not cramping.
Choice C is wrong because dehydration does not cause fever or persistent cramping.
Choice D is wrong because hypovolemic shock is a condition of low blood volume that causes low blood pressure, rapid pulse, and pale skin, not fever or cramping.
Correct Answer is A
Explanation
Asymmetrical chest movement is a sign of respiratory distress in the newborn, as it indicates unequal lung expansion or airway obstruction. A respiratory rate of 50 breaths/minute (choice B) is normal for a newborn, as is acrocyanosis (choice C), which is a bluish discoloration of the hands and feet due to immature peripheral circulation. Short periods of apnea (less than 15 seconds) (choice D) are also common and benign in newborns unless they are associated with bradycardia or cyanosis.
Choice B is not correct because a respiratory rate of 50 breaths/minute is within the normal range for a newborn.
Choice C is not correct because acrocyanosis is a normal finding in newborns and does not indicate respiratory distress.
Choice D is not correct because short periods of apnea (less than 15 seconds) are normal in newborns and do not indicate respiratory distress.
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