A nurse is disinfecting the room of a client who has a Clostridium difficultiesinfection. Which of the following solutions should the nurse use?
Chlorhexidine.
Isopropyl alcohol.
Chlorine bleach.
Triclosan.
The Correct Answer is C
According to the CDC1, chlorine bleach is an effective disinfectant for killing C. difficile spores on environmental surfaces.
It should be used in a 1:10 dilution of household bleach and water, freshly mixed daily.
Chlorine bleach can also kill other pathogens that may be present in the room of a client with C. difficile infection.
Choice A is wrong because chlorhexidine is not effective against C. difficile spores.
Chlorhexidine is an antiseptic that can be used for hand hygiene and surgical asepsis, but it does not kill spores.
Choice B is wrong because isopropyl alcohol is also not effective against C. difficile spores.
Alcohol-based hand sanitizers are not sufficient for preventing the spread of C. difficile, and soap and water should be used instead.
Choice D is wrong because triclosan is a type of antibacterial agent that is commonly found in some consumer products, such as soap and toothpaste. However, triclosan has no activity against C. difficile spores.
Triclosan may also contribute to antibiotic resistance and has potential adverse effects on human health and the environment.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is D
Explanation
The correct answer is choice D. Unequal height of the shoulders.
This is because scoliosis is a condition characterized by sideways curvature of the spine that can cause asymmetry of the shoulders, shoulder blades, and hips.
A scoliosis screening is a test that checks for this asymmetry by having the child bend forward from the waist and looking for any prominence of the rib cage or the spine.
Choice A is wrong because expansion of the upper intercostal spaces is not a sign of scoliosis, but rather a sign of hyperinflation of the lungs due to conditions such as asthma or emphysema.
Choice B is wrong because increased convex curve of the cervical spine is not a sign of scoliosis, but rather a sign of kyphosis, which is an excessive outward curvature of the upper spine.
Choice C is wrong because increased concave curve of the thoracic spine is not a sign of scoliosis, but rather a sign of lordosis, which is an excessive inward curvature of the lower spine.
Correct Answer is ["7"]
Explanation
Determine the total daily dose required in milligrams:
The prescribed dose is 80 mg/kg/day.
The child's weight is 35 kg.
Totaldailydose=80mg/kg/day×35kg
Calculate the total daily dose:
Totaldailydose=2800mg/day
Divide the total daily dose into four doses:
Doseperadministration: 2800mg/day ÷ 4 =700mg
Determine the volume of the oral suspension to administer per dose:
The available concentration of sucralfate oral suspension is 1 g/10 mL.
Convert 1 g to mg:
1g=1000mg.
Calculate the volume needed for 700 mg:
Volume(mL) = Desireddose(mg)÷Concentration(mg/mL)
Concentration = 1000mg÷10mL = 100mg/mL
Volume(mL) = 700 mg ÷ 100mg/mL
= 7 mL
Therefore, the nurse should administer 7 mL of sucralfate oral suspension per dose.
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