A nurse is caring for a patient who is receiving oxytocin injection intravenously for labor induction.The nurse should monitor this patient for which adverse effect of oxytocin?
Decrease in body temperature.
Maternal cardiac arrhythmias.
Urinary retention.
Insufficient relaxation of the uterus between contractions.
The Correct Answer is D
The correct answer is choice D. Insufficient relaxation of the uterus between contractions. This is also known as tachysystole or hyperstimulation, which can cause fetal distress and uterine rupture. Oxytocin is a hormone that stimulates uterine contractions, but it can also cause them to be too strong or too frequent if given in high doses or for too long.
Choice A is wrong because oxytocin does not decrease body temperature.
Choice B is wrong because oxytocin does not cause maternal cardiac arrhythmias.
Choice C is wrong because oxytocin does not cause urinary retention.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
The correct answer is choice C. Have a suction catheter available for use at delivery.This is because meconium-stained amniotic fluid indicates that the fetus has passed meconium (first stool) before birth, which can be a sign of fetal distress or hypoxia.Meconium can block the airways and cause breathing problems for the newborn, so suctioning the mouth and nose (or the trachea if needed) is important to prevent meconium aspiration syndrome.
Choice A is wrong because taking the mother’s vital signs every 15 minutes is not a specific intervention for meconium-stained amniotic fluid.
Vital signs should be monitored regularly during labor regardless of the fluid color.
Choice B is wrong because sending a specimen of the fluid to the laboratory for analysis is not a priority action.The color and consistency of the fluid can be observed by the nurse and documented.
The laboratory analysis will not change the immediate management of the newborn.
Choice D is wrong because preparing a slide of the fluid for fern testing is not relevant for meconium-stained amniotic fluid.
Fern testing is used to confirm the rupture of membranes by detecting a fern-like pattern of amniotic fluid under a microscope.It is not useful for assessing the presence or severity of meconium-stained amniotic fluid.
Correct Answer is B
Explanation
The correct answer is choice B: The risk of transplacental transmission of chlamydia between mother and baby is low.This means that the infection is unlikely to pass from the mother’s blood to the baby’s blood through the placenta.However, this does not mean that the infection is harmless for the baby.
Choice A is wrong because transmission of chlamydia usually occurs when the baby passes through the vagina.This can cause eye infections or pneumonia in the newborn.
Choice C is wrong because the baby has probably not developed antibodies to the chlamydia in utero.Antibodies are proteins that help fight infections, and they are usually passed from the mother to the baby through the placenta.However, chlamydia does not stimulate a strong antibody response in the mother, so there is little protection for the baby.
Choice D is wrong because the baby will not receive systemic treatment at birth to prevent a chlamydia infection.Systemic treatment means medication that affects the whole body, such as oral or intravenous antibiotics.The baby will only receive topical treatment, such as eye drops or ointment, to prevent eye infections.Normal ranges: Chlamydia infection is common among pregnant women, especially those under 25 years old or with risk factors such as multiple or new sexual partners.The prevalence of chlamydia among pregnant women in the United States ranges from 1% to 40%, depending on the population and screening methods.Chlamydia infection can be diagnosed by urine or swab tests, and treated with antibiotics such as azithromycin or doxycycline.Chlamydia screening is recommended for all pregnant women at their first prenatal visit and again in the third trimester if they are at high risk.
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