A newborn is jaundiced and receivesphototherapy via ultraviolet bank lights.
An appropriate nursing intervention when caring for an infant with hyperbilirubinemia and receiving phototherapy by this method would be to:
Apply an oil-based lotion to the newborn’s skin to prevent drying and cracking.
Limit the newborn’s intake of milk to prevent nausea, vomiting, and diarrhea.
Place eye shields over the newborn’s closed eyes.
Change the newborn’s position every 4 hours.
The Correct Answer is C
Placing eye shields over the newborn’s closed eyes. This is because phototherapy can cause eye damage and irritation to the newborn, so eye protection is essential.
Choice A is wrong because oil-based lotion can increase the absorption of heat and cause burns to the newborn’s skin.
Choice B is wrong because limiting the newborn’s intake of milk can cause dehydration and increase the risk of hyperbilirubinemia.
Choice D is wrong because changing the newborn’s position every 4 hours is not frequent enough to prevent pressure ulcers and ensure even exposure to the light.
Normal ranges for bilirubin levels in newborns are 1 to 12 mg/dL for term infants and 3 to 14 mg/dL for preterm infants. Phototherapy is usually indicated when the bilirubin level exceeds 15 mg/dL for term infants and 10 mg/dL for preterm infants.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is B
Explanation
This is because a patent ductus arteriosus is a congenital heart defect that involves a defect in which the fetal shunt between the aorta and the pulmonary artery fails to close. This causes a continuous machinery-like murmur that can be heard on auscultation.
Choice A is wrong because pulmonary stenosis is a narrowing of the pulmonary valve or artery that obstructs blood flow to the lungs. It causes a systolic ejection murmur that is best heard at the upper left sternal border.
Choice C is wrong because the ventricular septal defect is a hole in the wall between the ventricles that allows blood to flow from the left to the right side of the heart. It causes a loud, harsh holosystolic murmur that is best heard at the left lower sternal border.
Choice D is wrong because coarctation of the aorta is a narrowing of the aorta that reduces blood flow to the lower body. It causes a systolic murmur that radiates to the back and weak or absent femoral pulses.
Correct Answer is A
Explanation
choice A.
Infant of an Rh-negative mother and a father who is Rh-positive and homozygous for the Rh factor.
Rh incompatibility occurs when a woman is Rh-negative and her baby is Rh-positive. This can cause hemolytic disease of the neonate (HDN), a condition where the mother’s antibodies destroy the baby’s red blood cells.
Choice B is wrong because if both the mother and the baby are Rh-negative, there is no risk of Rh incompatibility.
Choice C is wrong because if the father is heterozygous for the Rh factor, there is a 50% chance that the baby will be Rh-negative and not affected by Rh incompatibility.
Choice D is wrong because if both the mother and the baby are Rh-positive, there is no risk of Rh incompatibility.
Whether you are a student looking to ace your exams or a practicing nurse seeking to enhance your expertise , our nursing education contents will empower you with the confidence and competence to make a difference in the lives of patients and become a respected leader in the healthcare field.
Visit Naxlex, invest in your future and unlock endless possibilities with our unparalleled nursing education contents today
Report Wrong Answer on the Current Question
Do you disagree with the answer? If yes, what is your expected answer? Explain.
Kindly be descriptive with the issue you are facing.