Which environmental factor is most significant when planning care for a client with osteomalacia?
Quiet, calm surroundings.
Stimulating sounds and activity.
Cool, moist air.
Frequent exposure to sunlight.
The Correct Answer is D
Choice D is correct because frequent exposure to sunlight is the most significant environmental factor when planning care for a client with osteomalacia. Osteomalacia is a condition in which the bones become soft and weak due to inadequate mineralization, often caused by vitamin D deficiency. Vitamin D is essential for calcium absorption and bone health, and it can be synthesized by the skin when exposed to sunlight. The nurse should encourage the client to get at least 15 minutes of sunlight per day or take vitamin D supplements as prescribed.
Choice A is incorrect because quiet, calm surroundings are not a specific environmental factor for a client with osteomalacia. Quiet, calm surroundings may help reduce stress and promote relaxation, but they do not affect bone mineralization or vitamin D synthesis.
Choice B is incorrect because stimulating sounds and activity are not a specific environmental factor for a client with osteomalacia. Stimulating sounds and activity may help improve mood and cognition, but they do not affect bone mineralization or vitamin D synthesis.
Choice C is incorrect because cool, moist air is not a specific environmental factor for a client with osteomalacia. Cool, moist air may help relieve respiratory symptoms or allergies, but it does not affect bone mineralization or vitamin D synthesis.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
Choice C is correct because pushing the undiluted Dextrose slowly through the currently infusing IV is the best way to administer the medication for a client with insulin shock. Insulin shock is a condition in which the blood glucose level drops too low due to excess insulin or insufficient food intake. This can cause symptoms such as confusion, sweating, tremors, or loss of consciousness. The nurse should administer 50% Dextrose IV as a bolus injection to raise the blood glucose level quickly and prevent brain damage.
Choice A is incorrect because asking the pharmacist to add the Dextrose to a TPN solution is not appropriate for a client with insulin shock. TPN stands for total parenteral nutrition, which is a type of intravenous feeding that provides all the nutrients needed by the body. TPN solutions contain dextrose, amino acids, lipids, vitamins, minerals, and electrolytes in specific concentrations and ratios. Adding extra dextrose to a TPN solution can alter its composition and cause complications such as hyperglycemia or fluid overload.
Choice B is incorrect because mixing the Dextrose in a 50 mL piggyback for a total volume of 100 mL is not effective for a client with insulin shock. A piggyback is a type of intravenous infusion that delivers medication through a secondary tubing attached to the primary tubing of another solution. Mixing the Dextrose in a piggyback can dilute its concentration and reduce its potency. It can also delay its delivery and onset of action.
Choice D is incorrect because diluting the Dextrose in one liter of 0.9% Normal Saline solution is not safe for a client with insulin shock. Normal Saline is a type of intravenous fluid that contains sodium chloride in isotonic concentration. Diluting the Dextrose in one liter of Normal Saline can lower its concentration and increase its volume significantly. This can cause complications such as hypoglycemia or fluid overload.
Correct Answer is ["30"]
Explanation
First, we need to find the concentration of insulin in the IV solution, which is the ratio of insulin units to saline volume. To do this, we use the given information that the IV solution contains 100 units in 250 ml. So, we divide 100 by 250 and get 0.4 units/ml.
Next, we need to calculate the infusion rate in ml/hour for the ordered dose of 12 units/hour. To do this, we use the ratio of insulin units to saline volume, which is 0.4 units/ml. So, we set up a proportion as follows:
0.4/1=12/x
To solve for x, we cross-multiply and get 0.4 x = 12. Then, we divide both sides by 0.4 and get x = 30. So, the infusion rate is 30 ml/hour.
Therefore, the nurse should program the infusion pump to deliver 30 ml/hour..
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