Robitussin DM contains 100 mg of guaifenesin per 1 teaspoon. How many milligrams of guaifenesin are in 10 mL?
200 mg
100 mg
75 mg
50 mg
The Correct Answer is A
Robitussin DM contains 100 mg of guaifenesin per 1 teaspoon. One teaspoon is equivalent to 5 milliliters, so 100 mg is present in 5 mL. Therefore, 10 mL of Robitussin DM contains 2 times the amount of guaifenesin in 1 teaspoon or 200 mg.
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Related Questions
Correct Answer is B
Explanation
To calculate the answer, we can use the following formula:.
(mg of drug required / total mg in vial) x total volume in vial = mL to administer. First, let's convert the dose from mg to g:.
80 mg = 0.08 g.
Next, let's plug in the values:. (0.08 g / 1 g) x 8 mL = 0.64 mL.
Therefore, the nurse should administer 0.64 mL of Solu-Medrol.
Correct Answer is C
Explanation
We need to calculate the patient's BSA using one of the available formulas. The most widely used formula is the Du Bois formula, which is:.
BSA = 0.007184 × W^0.425 × H^0.725.
where W is weight in kg and H is height in cm.. Plugging in the patient's weight and height, we get:. BSA = 0.007184 × 94.5^0.425 × 185^0.725
BSA = 2.15 m².
Now, we can use the physician's order to find the daily dose and the total dose of Platinol for this patient. The daily dose is:.
Daily dose = 20 mg/m²/day × BSA Daily dose = 20 mg/m²/day × 2.15 m² Daily dose = 43 mg/day.
The total dose for 5 days is:.
Total dose = Daily dose × Number of days Total dose = 43 mg/day × 5 days
Total dose = 215 mg.
Therefore, the patient's dose of Platinol would be 215 mg in total, or 43 mg per day for 5 days.
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