A nurse started a continuous IV infusion of 1 L of normal saline (NS) at 06:57, and the infusion is completed at 15:45. What is the flow rate of infusion in this situation?
114 mL/hr
124 mL/hr
125 mL/hr
130 mL/hr
The Correct Answer is A
The infusion was started at 06:57 and completed at 15:45, which is a total time of: 15 hours and 45 minutes - 6 hours and 57 minutes = 8 hours and 48 minutes
To calculate the flow rate, we need to know the total amount of fluid infused and divide it by the total time of infusion:
1 L = 1000 mL
Total time of infusion = 8 hours and 48 minutes = 528 minutes Flow rate = Total amount of fluid infused / Total time of infusion Flow rate = 1000 mL / 528 minutes
Flow rate = 1.89394 mL/min
To convert mL/min to mL/hr, we multiply by 60:
Flow rate = 1.89394 mL/min x 60 min/hr Flow rate = 113.6364 mL/hr
Therefore, the flow rate of infusion in this situation is approximately 114 mL/hr, which corresponds to option A.
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Related Questions
Correct Answer is A
Explanation
Robitussin DM contains 100 mg of guaifenesin per 1 teaspoon. One teaspoon is equivalent to 5 milliliters, so 100 mg is present in 5 mL. Therefore, 10 mL of Robitussin DM contains 2 times the amount of guaifenesin in 1 teaspoon or 200 mg.
Correct Answer is C
Explanation
To calculate the amount of diluent that should be added, we need to first calculate the volume of the final solution. .
The final concentration of ceftriaxone should be 600 mg/3 mL, which is the same as 200 mg/mL. .
If we have 1.5 g (or 1500 mg) of ceftriaxone, we can divide this by the desired concentration to get the total volume of the final solution:.
1500 mg ÷ 200 mg/mL = 7.5 mL.
So, the total volume of the final solution should be 7.5 mL. .
To calculate the amount of diluent needed, we need to subtract the volume of the ceftriaxone from the total volume of the final solution:.
7.5 mL - 0.00 mL = 7.5 mL.
Therefore, a nurse should add 7.5 mL of diluent to the vial containing 1.5 g of ceftriaxone to achieve a final concentration of 600 mg/3 mL.
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