A client is receiving intravenous infusion of 1.5 L saline solution at a rate of 75 mL/hr.
How many hours will it take to finish the infusion at the current rate?
20 hours
10 hours
15 hours
75 hours
The Correct Answer is A
To calculate the time it will take to finish the infusion, we can use the formula:
Time = Volume / Rate
Plugging in the given values, we get:
Time = 1.5 L / 75 mL/hr Converting 1.5 L to mL, we get:
Time = 1500 mL / 75 mL/hr Simplifying, we get:
Time = 20 hours
Therefore, it will take 20 hours to finish the infusion at the current rate.
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Related Questions
Correct Answer is C
Explanation
The patient is ordered to receive 0.15 mg/kg of Zofran over 15 minutes. The patient weighs 176 lb, which is equivalent to 80 kg. To calculate the total amount of Zofran the patient should receive, multiply the weight by the dosage:
80 kg x 0.15 mg/kg = 12 mg
The Zofran arrives from the pharmacy mixed in 50 mL of normal saline, which means there is 12 mg of Zofran in 50 mL of solution. To calculate how many milliliters per hour the nurse should set the IV pump, we can use the following formula:
50 mL / 0.25 hour = X mL per hour X = 200 mL per hour
Therefore, the nurse should set the IV pump to deliver 200 mL of Zofran per hour to the patient.
Correct Answer is C
Explanation
To calculate the amount of diluent that should be added, we need to first calculate the volume of the final solution. .
The final concentration of ceftriaxone should be 600 mg/3 mL, which is the same as 200 mg/mL. .
If we have 1.5 g (or 1500 mg) of ceftriaxone, we can divide this by the desired concentration to get the total volume of the final solution:.
1500 mg ÷ 200 mg/mL = 7.5 mL.
So, the total volume of the final solution should be 7.5 mL. .
To calculate the amount of diluent needed, we need to subtract the volume of the ceftriaxone from the total volume of the final solution:.
7.5 mL - 0.00 mL = 7.5 mL.
Therefore, a nurse should add 7.5 mL of diluent to the vial containing 1.5 g of ceftriaxone to achieve a final concentration of 600 mg/3 mL.
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