Ordered: Dopamine2mcg/kg/min In Stock: 200mg in 250mL Saline Patients weight: 60kg What rate would you set the pump to deliver the ordered medication? (Document to the nearest whole number)
The Correct Answer is ["9"]
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Dose in mcg/min=2 mcg/kg/min×60 kg=120 mcg/min
Convert this to mg/min since the concentration is in mg:
120 mcg/min=0.12 mg/min120 \text{ mcg/min} = 0.12 \text{ mg/min}120 mcg/min=0.12 mg/min
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Determine the concentration of Dopamine:
- Total amount of Dopamine: 200 mg in 250 mL of saline
- Concentration:
Concentration=200 mg250 mL=0.8 mg/mL\text{Concentration} = \frac{200 \text{ mg}}{250 \text{ mL}} = 0.8 \text{ mg/mL}Concentration=250 mL200 mg=0.8 mg/mL
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Calculate the pump rate in mL/min:
To find the rate in mL/min needed to deliver 0.12 mg/min:
Pump rate=Desired dose (mg/min)Concentration (mg/mL)\text{Pump rate} = \frac{\text{Desired dose (mg/min)}}{\text{Concentration (mg/mL)}}Pump rate=Concentration (mg/mL)Desired dose (mg/min)
Pump rate=0.12 mg/min0.8 mg/mL=0.15 mL/min\text{Pump rate} = \frac{0.12 \text{ mg/min}}{0.8 \text{ mg/mL}} = 0.15 \text{ mL/min}Pump rate=0.8 mg/mL0.12 mg/min=0.15 mL/min
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Convert the pump rate to mL/hour:
Multiply by 60 to convert from mL/min to mL/hour:
Pump rate=0.15 mL/min×60 min/hour=9 mL/hour\text{Pump rate} = 0.15 \text{ mL/min} \times 60 \text{ min/hour} = 9 \text{ mL/hour}Pump rate=0.15 mL/min×60 min/hour=9 mL/hour
So, you should set the pump to deliver Dopamine at a rate of 9 mL/hour.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is A
Explanation
The stages of shock are commonly described as the initial, compensatory, progressive, and refractory stages. Here is an explanation of each stage and why the patient's assessment findings correspond to the progressive stage:
B. The compensatory stage in (option B) is incorrect because, In the compensatory stage, the body continues to activate compensatory mechanisms to maintain perfusion. This includes increased heart rate, peripheral vasoconstriction, and shunting of blood to vital organs. The patient's assessment findings of decreasing cardiac output, decreased peripheral perfusion, and increased capillary permeability suggest that the body's compensatory mechanisms are no longer sufficient to maintain perfusion adequately. Therefore, the patient has progressed beyond the compensatory stage.
C. The initial stage in (option C) is incorrect because, In the initial stage, there is an initial insult or injury that triggers the shock state. The body's compensatory mechanisms are activated, such as increased heart rate and vasoconstriction, to maintain blood pressure and perfusion. However, the patient's assessment findings indicate that they have progressed beyond the initial stage.
D. The refractory stage in (option D) is incorrect because The refractory stage represents a severe and irreversible state of shock where vital organs fail, and despite interventions, the patient's condition does not improve. The patient's assessment findings do not suggest the refractory stage, as there is still potential for intervention and management.
Correct Answer is C
Explanation
This method, known as the 6-second method, involves counting the number of QRS complexes in a 6-second interval on the electrocardiogram (ECG) strip and then multiplying that number by 10 to calculate the heart rate per minute. The advantage of this method is that it provides a relatively quick estimate of the heart rate.
A. Printing a 1-minute ECG strip and counting the number of QRS complexes in (option A) is incorrect because it can be time-consuming and may not be practical in situations where a quick estimate is needed.
B. Calculating the number of small squares between one QRS complex and the next and dividing into 1500 in (option B) is incorrect because it is a method used to calculate heart rate, known as the "1500 method," but it is not as quick as the 6-second method and requires more time and measurement precision.
D. Counting the number of large squares in the R-R interval and dividing by 300 is another method used to calculate heart rate, known as the "300 method," but it is also less quick and less accurate for assessing heart rate in patients with regular rhythms.
It's important to note that if the heart rhythm is irregular, these methods may not provide an accurate estimate of the heart rate, and a longer monitoring period or a different approach may be necessary.
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