A woman is in active labor. On spontaneous rupture of her membranes, the nurse caring for this woman notices variable deceleration patterns during evaluation of the monitor tracing. When preparing to perform a vaginal examination, the nurse observes a small section of the umbilical cord protruding from the vagina. What should the nurse do next?
Wrap the cord loosely with a sterile towel saturated with warm normal saline.
Place a sterile gloved hand into the vagina and hold the presenting part off the cord while calling for assistance.
Increase the IV drip rate.
Administer oxygen to the woman via mask at 8 to 10 L/minute.
The Correct Answer is B
Choice A) Wrap the cord loosely with a sterile towel saturated with warm normal saline: This is not an appropriate action because it does not relieve the compression of the cord, which can cause fetal hypoxia and acidosis. The cord should be kept moist, but not wrapped around anything.
Choice B) Place a sterile gloved hand into the vagina and hold the presenting part off the cord while calling for assistance: This is the correct action because it prevents further descent of the fetus and reduces the pressure on the cord, which can improve fetal oxygenation and blood flow. The nurse should also elevate the woman's hips and place her in a knee-chest or Trendelenburg position to reduce gravity. The nurse should call for immediate assistance and prepare for an emergency cesarean section.
Choice C) Increase the IV drip rate: This is not an appropriate action because it does not address the cause of the variable decelerations, which is cord compression. Increasing the IV fluid may cause fluid overload and worsen maternal and fetal outcomes.
Choice D) Administer oxygen to the woman via mask at 8 to 10 L/minute: This is not an appropriate action because it does not relieve the cord compression, which is the main threat to fetal well-being. Oxygen administration may be helpful in some cases of fetal distress, but it is not sufficient in this situation.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is D
Explanation
Choice a) Urine output of 200 mL for the past 8 hours is incorrect because this is a normal finding for a postpartum woman. The average urine output for a healthy adult is about 800 to 2000 mL per day, which means about 100 to 250 mL per hour. Therefore, a urine output of 200 mL for the past 8 hours is within the normal range and does not indicate any complications.
Choice b) Weight decrease of 2 pounds since delivery is incorrect because this is also a normal finding for a postpartum woman. The weight loss is due to the expulsion of the placenta, amniotic fluid, and blood during delivery. A postpartum woman can expect to lose about 10 to 12 pounds immediately after giving birth, and another 5 pounds in the following weeks due to fluid loss. Therefore, a weight decrease of 2 pounds since delivery is not a cause for concern and does not need to be reported to the obstetrician.
Choice c) Pulse rate of 65 beats per minute is incorrect because this is also a normal finding for a postpartum woman. The normal resting pulse rate for an adult ranges from 60 to 100 beats per minute, and it may decrease slightly after delivery due to blood loss and reduced cardiac output. Therefore, a pulse rate of 65 beats per minute is not indicative of any problems and does not require any intervention.
Choice d) Drop in hematocrit of 6% since admission is correct because this is an abnormal finding for a postpartum woman and suggests that she has developed anemia due to excessive blood loss. Hematocrit is the percentage of red blood cells in the blood, and it reflects the oxygen-carrying capacity of the blood. The normal hematocrit range for an adult female is 37% to 47%, and it may decrease slightly after delivery due to hemodilution. However, a drop in hematocrit of more than 10% from the baseline or below 30% indicates severe anemia and requires immediate treatment. Therefore, a drop in hematocrit of 6% since admission is a significant change that should be reported to the obstetrician as soon as possible.
Correct Answer is D
Explanation
Choice A) Obtain an oxygen saturation: This is not a priority action because it does not address the underlying cause of the respiratory distress, which is meconium aspiration. Meconium aspiration can cause airway obstruction, inflammation, infection, and pulmonary hypertension in the newborn. Oxygen saturation may be low, but it is not a reliable indicator of the severity of the condition.
Choice B) Stimulate the baby to increase respirations: This is not a priority action because it may worsen the respiratory distress by increasing the work of breathing and causing more meconium to be aspirated. Stimulation may also cause stress and hypoxia in the newborn.
Choice C) Prepare to initiate ECMO: This is not a priority action because it is a last resort treatment for severe cases of meconium aspiration syndrome that do not respond to conventional therapies. ECMO stands for extracorporeal membrane oxygenation, which is a form of life support that bypasses the lungs and provides oxygen to the blood.
ECMO has many risks and complications, such as bleeding, infection, and organ damage. It should only be used when other options have failed and with the consent of the parents.
Choice D) Notify the provider at once: This is the correct action because it allows for prompt assessment and intervention by the provider, who can initiate appropriate treatments for meconium aspiration syndrome. These may include suctioning of the airway, administration of antibiotics, surfactant, or inhaled nitric oxide, and mechanical ventilation . Early treatment can improve the outcomes and reduce the complications of meconium aspiration syndrome.
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