A small, round raised area appears under the client's skin as the nurse administers an intradermal medication. Which action should the nurse take?
Document the site where the medication was given.
Notify the healthcare provider of the allergic response.
Elevate the area and apply light pressure over the site.
Apply a cold pack to the area for twenty minutes.
The Correct Answer is A
Choice A reason: The appearance of a small, round raised area, known as a wheal, is a normal reaction to an intradermal injection and should be documented.
Choice B reason: This is not an allergic response but a normal reaction to an intradermal injection, so there is no need to notify the healthcare provider.
Choice C reason: There is no need to elevate the area or apply pressure as the raised area is a normal reaction to the medication being correctly placed in the dermis.
Choice D reason: Applying a cold pack is not necessary for a normal reaction to an intradermal injection.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is D
Explanation
Choice A reason: Offering comfort that healing can happen at any point in time may not be appropriate for a client in the terminal stage of lung cancer, as it may give false hope.
Choice B reason: Offering strategies to provide comfort to the client can be helpful, but it does not address the spouse's immediate emotional needs.
Choice C reason: Suggesting that the spouse go home to sleep may seem dismissive of the spouse's current emotional state and need for support.
Choice D reason: Explaining that the staff will strive to keep the client comfortable addresses the spouse's concern for the client's well-being and provides reassurance about the care being provided.
Correct Answer is ["0.8"]
Explanation
Amount (mg) ÷ Concentration (mg/mL) = Volume (mL)
Step 1: The amount of hydromorphone the patient needs is 3 mg. Step 2: The concentration of the hydromorphone solution is 4 mg/mL. Step 3: Substitute the values into the formula: 3 mg ÷ 4 mg/mL.
Step 4: Calculate the volume: 3 ÷ 4 = 0.75 mL. 0.8 rounded to the nearest tenth
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