A nurse is reviewing the laboratory results of a client who is dehydrated. Which of the following BUN lab values should the nurse report to the provider?

10 mg/dL.

18 mg/dL.

13 mg/dL.

25 mg/dL.

Answer and Explanation

The Correct Answer is D

25 mg/dL.

Choice A rationale:

A BUN (Blood Urea Nitrogen) level of 10 mg/dL is within the normal range, indicating normal kidney function. There is no indication to report this value to the provider for a dehydrated client.

Choice B rationale:

A BUN level of 18 mg/dL is within the normal range as well. This value does not suggest significant dehydration, so it is not necessary to report it to the provider in this context.

Choice C rationale:

A BUN level of 13 mg/dL is also within the normal range, and similar to choices A and B, it does not indicate severe dehydration that requires immediate reporting to the provider.

Choice D rationale:

A BUN level of 25 mg/dL is elevated, which may indicate dehydration, kidney dysfunction, or other issues affecting fluid balance. Since the client is dehydrated, this elevated value needs to be reported to the provider for further evaluation and appropriate intervention.

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Correct Answer is D

Explanation

The correct answer is choice D: Reduction of T-wave amplitude.

Choice A rationale:

The amplitude of the QRS complex is not directly affected by changes in serum potassium levels. It represents ventricular depolarization, and its restoration would not be an expected outcome of polystyrene sulfonate treatment

Choice B rationale:

Shortening of the P-wave duration is not an expected change with polystyrene sulfonate treatment. The P-wave represents atrial depolarization, which is not significantly impacted by the administration of this medication

Choice C rationale:

Widening of the QRS complex is associated with high serum potassium levels. The goal of polystyrene sulfonate treatment is to lower potassium levels and, thus, return the QRS complex to its normal width

Choice D rationale:

Polystyrene sulfonate aims to reduce serum potassium levels. When effective, this should result in a reduction of T-wave amplitude, which is a common ECG change seen with hyperkalemia

In conclusion, choice D is the correct answer, as a reduction in T-wave amplitude would be the expected change on the client's ECG if polystyrene sulfonate effectively lowers their serum potassium level.

A. Respiratory acidosis. B. Metabolic acidosis. C. Metabolic alkalosis. D. Respiratory alkalosis.

Correct Answer is A

Explanation

Choice A rationale:

The arterial blood gas results show a low pH (acidosis) and an elevated Paco2 (partial pressure of carbon dioxide), which indicates respiratory acidosis. This condition occurs when there is inadequate removal of carbon dioxide through ventilation, leading to an accumulation of carbonic acid in the blood and a decrease in pH.

Choice B rationale:

Metabolic acidosis would present with a low pH and a low bicarbonate (HCO3-) level, not an elevated Paco2.

Choice C rationale:

Metabolic alkalosis would present with a high pH and an elevated bicarbonate (HCO3-) level, not an elevated Paco2.

Choice D rationale:

Respiratory alkalosis would present with a high pH and a decreased Paco2, not an elevated Paco2 as seen in this case.

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A nurse is reviewing the laboratory results of a client who is dehydrated. Which of the following BUN lab values should the nurse report to the provider?

Nursing Test Bank

Naxlex Comprehensive Predictor Exams

A nurse is caring for a client who has a serum potassium level of 5.5 mEq/L. The provider prescribes polystyrene sulfonate. If this medication is effective, the nurse should expect which of the following changes on the client's ECG?

Correct Answer is D

Explanation

A nurse is caring for a client whose arterial blood gas results show a pH of 7.3 and a Paco2 of 50 mm Hg. The nurse should identify that the client is experiencing which of the following acid-base imbalances?

Correct Answer is A

Explanation

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