A nurse is reviewing the laboratory results of a client who is dehydrated. Which of the following BUN lab values should the nurse report to the provider?

10 mg/dL.

18 mg/dL.

13 mg/dL.

25 mg/dL.

Answer and Explanation

The Correct Answer is D

25 mg/dL.

Choice A rationale:

A BUN (Blood Urea Nitrogen) level of 10 mg/dL is within the normal range, indicating normal kidney function. There is no indication to report this value to the provider for a dehydrated client.

Choice B rationale:

A BUN level of 18 mg/dL is within the normal range as well. This value does not suggest significant dehydration, so it is not necessary to report it to the provider in this context.

Choice C rationale:

A BUN level of 13 mg/dL is also within the normal range, and similar to choices A and B, it does not indicate severe dehydration that requires immediate reporting to the provider.

Choice D rationale:

A BUN level of 25 mg/dL is elevated, which may indicate dehydration, kidney dysfunction, or other issues affecting fluid balance. Since the client is dehydrated, this elevated value needs to be reported to the provider for further evaluation and appropriate intervention.

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Correct Answer is A

Explanation

Choice A rationale:

The arterial blood gas results show a low pH (acidosis) and an elevated Paco2 (partial pressure of carbon dioxide), which indicates respiratory acidosis. This condition occurs when there is inadequate removal of carbon dioxide through ventilation, leading to an accumulation of carbonic acid in the blood and a decrease in pH.

Choice B rationale:

Metabolic acidosis would present with a low pH and a low bicarbonate (HCO3-) level, not an elevated Paco2.

Choice C rationale:

Metabolic alkalosis would present with a high pH and an elevated bicarbonate (HCO3-) level, not an elevated Paco2.

Choice D rationale:

Respiratory alkalosis would present with a high pH and a decreased Paco2, not an elevated Paco2 as seen in this case.

A. Sweet Potatoes. B. Bananas. C. Grapes. D. Watermelon.

Correct Answer is ["A","B","D"]

Explanation

The correct answer is choices A, B, and D. Here are the rationales for each choice:

Choice A rationale:

Sweet potatoes are an excellent source of potassium. One medium sweet potato contains about 542 mg of potassium, making it a great option for a high-potassium diet.

Choice B rationale:

Bananas are well-known for their high potassium content. A medium banana provides approximately 451 mg of potassium, which is beneficial for maintaining proper muscle and nerve function.

Choice C rationale:

Grapes are not particularly high in potassium compared to other fruits. They contain some potassium, but not enough to be considered a significant source for a high-potassium diet.

Choice D rationale:

Watermelon is a good source of potassium. Two wedges of watermelon contain about 640 mg of potassium, making it a suitable choice for increasing potassium intake.

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A nurse is reviewing the laboratory results of a client who is dehydrated. Which of the following BUN lab values should the nurse report to the provider?

Nursing Test Bank

Naxlex Comprehensive Predictor Exams

A nurse is caring for a client whose arterial blood gas results show a pH of 7.3 and a Paco2 of 50 mm Hg. The nurse should identify that the client is experiencing which of the following acid-base imbalances?

Correct Answer is A

Explanation

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Correct Answer is ["A","B","D"]

Explanation

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