A nurse is reviewing a client's laboratory values and discovers the client has a serum potassium of 6.2 mEq/L. Which of the following interventions should the nurse anticipate?
Administering a potassium-sparing diuretic.
Administering sodium polystyrene sulfonate.
Initiating an IV potassium infusion.
Encouraging the client to eat bananas.
The Correct Answer is B
The correct answer is choice B) Administering sodium polystyrene sulfonate.
Choice A rationale:
Administering a potassium-sparing diuretic is not appropriate for a client with hyperkalemia (high potassium levels). Potassium-sparing diuretics would further increase potassium levels, worsening the condition.
Choice B rationale:
Sodium polystyrene sulfonate is used to treat hyperkalemia. It works by exchanging sodium ions for potassium ions in the intestines, which helps to lower serum potassium levels by excreting it through the stool.
Choice C rationale:
Initiating an IV potassium infusion would be contraindicated in this situation as it would increase the already elevated potassium levels, potentially leading to dangerous cardiac complications.
Choice D rationale:
Encouraging the client to eat bananas is not advisable because bananas are high in potassium, which would exacerbate hyperkalemia.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is B
Explanation
Respiratory acidosis.
Choice A rationale:
Metabolic alkalosis occurs when there is an increase in pH and bicarbonate (HCO₃⁻) levels, which is not the case here. The pH value in this scenario is 7.22, indicating acidosis.
Choice B rationale:
Respiratory acidosis results from the retention of carbon dioxide (PaCO₂) in the blood, leading to a decrease in pH. In this case, the pH is low (7.22), and the PacO₂ is elevated (68 mm Hg), supporting the diagnosis of respiratory acidosis.
Choice C rationale:
Metabolic acidosis is characterized by a decrease in pH and bicarbonate levels, along with a possible negative base excess. However, in this scenario, the base excess is -2, which does not indicate metabolic acidosis.
Choice D rationale:
Respiratory alkalosis occurs when there is a decrease in PaCO₂, leading to an increase in blood pH. The ABG values provided (pH 7.22, PacO₂ 68 mm Hg) are not consistent with respiratory alkalosis.
Correct Answer is A
Explanation
Choice A rationale:
The client with a phosphate level of 5.7 mg/dL likely has a manifestation of hypoparathyroidism. Hypoparathyroidism leads to decreased parathyroid hormone (PTH) secretion, which causes increased renal phosphate reabsorption, leading to elevated phosphate levels in the blood.
Choice B rationale:
A calcium level of 9.8 mg/dL is within the normal range (8.5-10.2 mg/dL) and does not indicate hypoparathyroidism.
Choice C rationale:
A vitamin D level of 25 ng/mL is within the normal range (30-100 ng/mL) and does not suggest hypoparathyroidism.
Choice D rationale:
A magnesium level of 1.8 mEq/L is within the normal range (1.7-2.2 mEq/L) and does not directly indicate hypoparathyroidism.
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