A newborn in the nursery is exhibiting signs of intrauterine drug exposure. Which of the following signs/symptoms is the nurse observing? (Select all that apply)
Calm, easy to comfort
Tremors
Persistent shrill cry
Difficult to console
Correct Answer : B,C,D
Choice A) Calm, easy to comfort is incorrect because this is not a sign of intrauterine drug exposure, but rather a sign of normal or healthy newborn behavior. Newborns who are calm and easy to comfort are usually well-adjusted and have a good temperament. They respond positively to soothing techniques such as holding, rocking, or singing.
They do not show signs of distress or withdrawal, which are common in newborns who are exposed to drugs in utero. Therefore, this response is irrelevant and inaccurate.
Choice B) Tremors is correct because this is a sign of intrauterine drug exposure that can indicate neurological damage or withdrawal syndrome. Tremors are involuntary shaking or quivering movements of the body or limbs that occur due to abnormal electrical activity in the brain or nervous system. Newborns who are exposed to drugs such as opioids, cocaine, or alcohol in utero may develop tremors as a result of brain injury, hypoxia, hypoglycemia, or seizures. They may also experience tremors as a symptom of neonatal abstinence syndrome (NAS), which is a condition that occurs when the newborn stops receiving the drug from the mother and goes through withdrawal. NAS can cause various physical and behavioral problems in the newborn, such as irritability, poor feeding, vomiting, diarrhea, sweating, fever, or seizures. Therefore, this response is clear and accurate.
Choice C) Persistent shrill cry is correct because this is a sign of intrauterine drug exposure that can indicate pain or discomfort in the newborn. Crying is a normal and natural way for newborns to communicate their needs and feelings. However, some newborns who are exposed to drugs such as opioids, cocaine, or alcohol in utero may cry more often, louder, or longer than usual. They may have a high-pitched or piercing cry that is difficult to soothe or stop. This may be due to various factors such as hunger, colic, infection, injury, or withdrawal. A persistent shrill cry can also affect the bonding and attachment between the newborn and the parents or caregivers. Therefore, this response is clear and accurate.
Choice D) Difficult to console is correct because this is a sign of intrauterine drug exposure that can indicate emotional or behavioral problems in the newborn. Newborns who are difficult to console are usually unhappy and restless. They do not respond well to soothing techniques such as holding, rocking, or singing. They may have trouble sleeping, feeding, or interacting with others. They may also show signs of agitation, anxiety, or depression. These problems may be caused by exposure to drugs such as opioids, cocaine, or alcohol in utero, which can affect the development and function of the brain and nervous system. They may also be influenced by the environment and relationship of the newborn with the parents or caregivers. Therefore, this response is clear and accurate.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is D
Explanation
Choice A) Obtain an oxygen saturation: This is not a priority action because it does not address the underlying cause of the respiratory distress, which is meconium aspiration. Meconium aspiration can cause airway obstruction, inflammation, infection, and pulmonary hypertension in the newborn. Oxygen saturation may be low, but it is not a reliable indicator of the severity of the condition.
Choice B) Stimulate the baby to increase respirations: This is not a priority action because it may worsen the respiratory distress by increasing the work of breathing and causing more meconium to be aspirated. Stimulation may also cause stress and hypoxia in the newborn.
Choice C) Prepare to initiate ECMO: This is not a priority action because it is a last resort treatment for severe cases of meconium aspiration syndrome that do not respond to conventional therapies. ECMO stands for extracorporeal membrane oxygenation, which is a form of life support that bypasses the lungs and provides oxygen to the blood.
ECMO has many risks and complications, such as bleeding, infection, and organ damage. It should only be used when other options have failed and with the consent of the parents.
Choice D) Notify the provider at once: This is the correct action because it allows for prompt assessment and intervention by the provider, who can initiate appropriate treatments for meconium aspiration syndrome. These may include suctioning of the airway, administration of antibiotics, surfactant, or inhaled nitric oxide, and mechanical ventilation . Early treatment can improve the outcomes and reduce the complications of meconium aspiration syndrome.
Correct Answer is D
Explanation
Choice A: This is incorrect because lanugo is a fine, downy hair that covers the fetus in utero. It usually disappears by the 36th week of gestation, but it may persist in some preterm infants. Lanugo helps to retain body heat and protect the skin from amniotic fluid. Lanugo is not a sign of postmaturity, but of prematurity or intrauterine growth restriction.
Choice B: This is incorrect because a short, chubby appearance is typical of a term infant, who is born between 37 and 42 weeks of gestation. A term infant has a well-developed subcutaneous fat layer that gives them a rounded shape and smooth skin. A term infant also has a head circumference that is proportional to their body length and weight. A short, chubby appearance is not a sign of postmaturity, but of normal development.
Choice C: This is incorrect because vernix caseosa is a white, cheesy substance that covers the fetus in utero. It usually decreases by the 40th week of gestation, but it may remain in some term infants, especially in the skin folds. Vernix caseosa helps to moisturize and protect the skin from amniotic fluid and infection. Vernix caseosa is not a sign of postmaturity, but of term or near-term gestation.
Choice D: This is the correct answer because cracked, peeling skin is a common sign of postmaturity, which occurs when the infant is born after 42 weeks of gestation. A postmature infant has a loss of subcutaneous fat and water that results in dry, wrinkled, and desquamated skin. A postmature infant also has a large head circumference that is disproportionate to their body length and weight. Cracked, peeling skin indicates prolonged exposure to amniotic fluid and placental insufficiency.
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