A client who has been on a mechanical ventilator for three days develops a fever of 101 degrees Fahrenheit green sputum, and right lower lobe crackles. The nurse contacts the physician regarding possible development of which complication?
Ventilator -associated pneumonia
Pulmonary embolism
Stress ulcer
Pneumothorax
The Correct Answer is A
A) Ventilator-associated pneumonia (VAP):
Ventilator-associated pneumonia (VAP) is a type of pneumonia that develops in patients who have been on mechanical ventilation for more than 48 hours. It is a common and serious complication in critically ill patients on ventilators. Symptoms such as fever, green sputum, and right lower lobe crackles are indicative of a respiratory infection, which, in this case, is most likely VAP. VAP typically presents with signs of infection such as elevated temperature, purulent sputum, and new infiltrates on a chest x-ray, in addition to lung crackles.
B) Pulmonary embolism (PE):
Although pulmonary embolism (PE) can cause symptoms like tachypnea, chest pain, and dyspnea, it does not typically cause a fever, green sputum, or localized crackles in the lungs. PE is usually characterized by sudden onset of respiratory distress, often accompanied by hemoptysis or chest pain, and would not typically present with the localized findings in the lower lobe (e.g., crackles).
C) Stress ulcer:
Stress ulcers can occur in critically ill patients, especially those on mechanical ventilation, due to the stress response and reduced blood flow to the stomach. However, stress ulcers typically cause gastrointestinal symptoms, such as melena (black, tarry stools) or hematemesis (vomiting blood).
D) Pneumothorax:
A pneumothorax occurs when air accumulates in the pleural space, causing a collapse of the lung. It can lead to symptoms such as sudden chest pain, dyspnea, and diminished breath sounds on one side of the chest. However, it would not typically cause fever, green sputum, or localized crackles.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is A
Explanation
A) Be placed in isolation to prevent radiation exposure to others:
Radioactive iodine (I-131) is commonly used to treat thyroid cancer because it targets and destroys thyroid tissue, including any remaining cancerous cells. This treatment involves the administration of a radioactive substance that can be excreted through saliva, urine, and sweat. To minimize radiation exposure to others, patients are often placed in isolation, particularly in a hospital setting, for a period following administration.
B) Avoid consuming any food or fluids for 24 hours prior to the treatment:
While it’s essential for patients to follow specific instructions regarding food and fluid intake, such as avoiding certain foods or fluids that may interfere with absorption or increase the risk of side effects (like dairy products), the patient does not need to avoid all food and fluids for 24 hours after receiving radioactive iodine.
C) Avoid all physical activity for six weeks after the treatment:
While some precautions, such as avoiding close contact with others for a short period of time, may be necessary, avoiding physical activity for six weeks is not usually required. Patients may be advised to take it easy during the initial recovery phase, but they can typically resume normal activities once the initial isolation period is complete and their radiation exposure is below safety thresholds.
D) Discontinue all other medications for a week before treatment:
However, certain medications that affect thyroid function (such as thyroid hormones or antithyroid medications) may need to be adjusted or stopped before treatment to ensure the effectiveness of the radioactive iodine. The specifics would depend on the patient’s condition and the healthcare provider’s instructions.
Correct Answer is ["90"]
Explanation
Given:
Ordered dose of Alteplase: 0.9 mg/kg
Client weight: 220 pounds
Step 1: Convert the client's weight from pounds to kilograms:
1 pound (lb) = 0.453592 kilograms (kg)
Client weight in kg = 220 lbs x 0.453592 kg/lb = 99.76824 kg
Step 2: Calculate the total dose of Alteplase:
Total dose (mg) = Ordered dose (mg/kg) xClient weight (kg)
Total dose (mg) = 0.9 mg/kg x 99.76824 kg
Total dose (mg) = 89.801416 mg
Step 3: Round to the nearest whole number:
Total dose (mg) ≈ 90 mg
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