Which finding would alert the nurse to suspect that a newborn is experiencing respiratory distress?
asymmetrical chest movement
respiratory rate of 50 breaths/minute
acrocyanosis
short periods of apnea (less than 15 seconds)
The Correct Answer is A
Asymmetrical chest movement is a sign of respiratory distress in the newborn, as it indicates unequal lung expansion or airway obstruction. A respiratory rate of 50 breaths/minute (choice B) is normal for a newborn, as is acrocyanosis (choice C), which is a bluish discoloration of the hands and feet due to immature peripheral circulation. Short periods of apnea (less than 15 seconds) (choice D) are also common and benign in newborns unless they are associated with bradycardia or cyanosis.
Choice B is not correct because a respiratory rate of 50 breaths/minute is within the normal range for a newborn.
Choice C is not correct because acrocyanosis is a normal finding in newborns and does not indicate respiratory distress.
Choice D is not correct because short periods of apnea (less than 15 seconds) are normal in newborns and do not indicate respiratory distress.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is D
Explanation
Determine the client’s temperature. This is because shaking chills during the immediate postpartum period can be a sign of infection, such as endometritis or mastitis. Infection is a serious complication that can lead to sepsis and shock if not treated promptly. The nurse should measure the client’s temperature and look for other signs of infection, such as foul-smelling lochia, breast tenderness, or tachycardia.
Choice A is wrong because placing the client on seizure precautions is not indicated for shaking chills. Seizure precautions are used for clients who have eclampsia or other conditions that increase the risk of seizures.
Choice B is wrong because covering the client with warm blankets may not be helpful for shaking chills. Warm blankets may increase the body temperature and worsen the infection.
Choice C is wrong because notifying the charge nurse is not the first action the nurse should take. The nurse should assess the client’s condition before reporting to the charge nurse or the provider.
Correct Answer is C
Explanation
Notify the physician of a possible pulmonary embolism. This is because the client's symptoms suggest that she has a pulmonary embolism, which is a blockage of a blood vessel in the lungs often caused by blood clots that travel from the legs. Pulmonary embolism is a life-threateningcondition that requires immediate medical attention. The client may also have chest pain, coughing up blood, dizziness, or fainting.
Choice A is wrong because postpartum mucous membrane congestion does not cause fever, cough, or shortness of breath.
Choice B is wrong because an upper respiratory infection does not cause edema and redness along the saphenous vein.
Choice D is wrong because an antipyretic remedy does not treat the underlying cause of the fever and may mask the severity of the condition.
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