Which finding would alert the nurse to suspect that a newborn is experiencing respiratory distress?
asymmetrical chest movement
respiratory rate of 50 breaths/minute
acrocyanosis
short periods of apnea (less than 15 seconds)
The Correct Answer is A
Asymmetrical chest movement is a sign of respiratory distress in the newborn, as it indicates unequal lung expansion or airway obstruction. A respiratory rate of 50 breaths/minute (choice B) is normal for a newborn, as is acrocyanosis (choice C), which is a bluish discoloration of the hands and feet due to immature peripheral circulation. Short periods of apnea (less than 15 seconds) (choice D) are also common and benign in newborns unless they are associated with bradycardia or cyanosis.
Choice B is not correct because a respiratory rate of 50 breaths/minute is within the normal range for a newborn.
Choice C is not correct because acrocyanosis is a normal finding in newborns and does not indicate respiratory distress.
Choice D is not correct because short periods of apnea (less than 15 seconds) are normal in newborns and do not indicate respiratory distress.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is B
Explanation
Sudden infant death syndrome (SIDS) is the sudden and unexplained death of an infant under one year of age. SIDS is more likely to occur when infants sleep on their stomachs or sides, or when they are propped up with pillows or other soft bedding. These positions can interfere with the infant's breathing and increase the risk of suffocation or overheating .
Choice A is incorrect because gastroesophageal reflux (GER) is a common condition in infants that causes them to spit up frequently after feeding. GER does not increase the risk of SIDS and can be managed by feeding smaller amounts, burping the infant often, and keeping them upright for a while after feeding.
Choice C is incorrect because apnea episodes are brief pauses in breathing that occur normally in infants, especially during sleep. Apnea episodes do not increase the risk of SIDS and usually resolve by six months of age.
Choice D is incorrect because sleeping for short intervals is normal for newborns, who need to feed frequently during the day and night. Sleeping for short intervals does not increase the risk of SIDS and will gradually change as the infant grows older.
Correct Answer is D
Explanation
Hemorrhage. This is because postpartum hemorrhage (PPH) is severe bleeding and loss of blood after childbirth that can lead to death. The most common cause of PPH is the uterus not contracting properly after delivery. The nurse needs to monitor the client’s pulse and blood pressure frequently to detect signs of shock and blood loss.
Choice A is wrong because thromboembolism is a blood clot that blocks a blood vessel, not a complication of bleeding.
Choice B is wrong because cervical laceration is a tear in the cervix that can cause bleeding, but it is not a common cause of PPH.
Choice C is wrong because hemorrhoids are swollen veins in the anus or rectum that can cause bleeding, but they are not a common cause of PPH.
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