Which finding would alert the nurse to suspect that a newborn is experiencing respiratory distress?
asymmetrical chest movement
respiratory rate of 50 breaths/minute
acrocyanosis
short periods of apnea (less than 15 seconds)
The Correct Answer is A
Asymmetrical chest movement is a sign of respiratory distress in the newborn, as it indicates unequal lung expansion or airway obstruction. A respiratory rate of 50 breaths/minute (choice B) is normal for a newborn, as is acrocyanosis (choice C), which is a bluish discoloration of the hands and feet due to immature peripheral circulation. Short periods of apnea (less than 15 seconds) (choice D) are also common and benign in newborns unless they are associated with bradycardia or cyanosis.
Choice B is not correct because a respiratory rate of 50 breaths/minute is within the normal range for a newborn.
Choice C is not correct because acrocyanosis is a normal finding in newborns and does not indicate respiratory distress.
Choice D is not correct because short periods of apnea (less than 15 seconds) are normal in newborns and do not indicate respiratory distress.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
Tachycardia. Tachycardia is a sign of hypovolemic shock from postpartum hemorrhage, which occurs when the blood volume is reduced and the heart rate increases to compensate for the low cardiac output and tissue perfusion. Tachycardia is usually the first sign of hypovolemic shock, as it can occur even before a significant drop in blood pressure or other symptoms.
Choice A. Hypotension is incorrect because it is a late sign of hypovolemic shock, which occurs when the compensatory mechanisms fail to maintain adequate blood pressure and organ perfusion.
Choice B. Cold, clammy skin is incorrect because it is a sign of peripheral vasoconstriction, which occurs as a compensatory mechanism to divert blood flow to the vital organs. However, it is not specific to hypovolemic shock and can occur in other types of shock as well.
Choice D. Decreased urinary output is incorrect because it is a sign of renal impairment, which occurs as a result of reduced blood flow to the kidneys. However, it is not specific to hypovolemic shock and can occur in other types of shock or renal disorders as well.
Correct Answer is D
Explanation
This can be from the sudden withdrawal of your hormones. It is not a cause for alarm. This is because newborn female babies may have a little bloody vaginal discharge in their diapers due to the withdrawal of maternal hormones after delivery. This usually stops as the hormones return to normal levels. The nurse should reassure the mother that this is a normal and harmless phenomenon and does not require any treatment.
Choice A is wrong because the blood is not related to cleaning her perineal area. The nurse should not blame the mother for being careless.
Choice B is wrong because the baby does not need an appointment for this condition. The nurse should not alarm the mother unnecessarily.
Choice C is wrong because the mother does not need to watch her baby for this condition. The nurse should not leave the mother in doubt or anxiety.
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