The first sign of hypovolemic shock from postpartum hemorrhage is likely to be:
Hypotension
Cold, clammy skin
Tachycardia
Decreased urinary output
The Correct Answer is C
Tachycardia. Tachycardia is a sign of hypovolemic shock from postpartum hemorrhage, which occurs when the blood volume is reduced and the heart rate increases to compensate for the low cardiac output and tissue perfusion. Tachycardia is usually the first sign of hypovolemic shock, as it can occur even before a significant drop in blood pressure or other symptoms.
Choice A. Hypotension is incorrect because it is a late sign of hypovolemic shock, which occurs when the compensatory mechanisms fail to maintain adequate blood pressure and organ perfusion.
Choice B. Cold, clammy skin is incorrect because it is a sign of peripheral vasoconstriction, which occurs as a compensatory mechanism to divert blood flow to the vital organs. However, it is not specific to hypovolemic shock and can occur in other types of shock as well.
Choice D. Decreased urinary output is incorrect because it is a sign of renal impairment, which occurs as a result of reduced blood flow to the kidneys. However, it is not specific to hypovolemic shock and can occur in other types of shock or renal disorders as well.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is A
Explanation
Endometritis. This is because the client's symptoms suggest that she has endometritis, which is an infection of the lining of the uterus. Endometritis is a common postpartum complication that can occur after vaginal or cesarean delivery. The client may also have foul-smelling vaginal discharge, chills, and fatigue.
Choice B is wrong because cystitis is an infection of the bladder that causes pain or burning during urination, not cramping.
Choice C is wrong because dehydration does not cause fever or persistent cramping.
Choice D is wrong because hypovolemic shock is a condition of low blood volume that causes low blood pressure, rapid pulse, and pale skin, not fever or cramping.
Correct Answer is B
Explanation
Jaundice in an infant who is 4-hr old. This is because jaundice is a yellow discoloration of the skin and eyes caused by high levels of bilirubin in the blood. Jaundice usually appears between the second and fourth day after birth and lasts for one to two weeks. Jaundice that appears within the first 24 hours of life is considered early-onset jaundice and may indicate a serious problem, such as an infection, a blood type mismatch, or a liver disorder. The nurse should notify the charge nurse of this finding and request a blood test to check the bilirubin level.

Choice A is wrong because a hematocrit of 60% in an infant who is 8-hr old is not abnormal. Hematocrit is the percentage of red blood cells in the blood. Newborns normally have higher hematocrit levels than older children and adults because they have more red blood cells at birth.
Choice C is wrong because a blood glucose fingerstick of 40 mg/dL for an infant who is 1-hr old is not abnormal.
Blood glucose is the amount of sugar in the blood. Newborns normally have lower blood glucose levels than older children and adults because they have less glycogen (stored sugar) at birth.
Choice D is wrong because acrocyanosis in an infant who is 2-hr old is not abnormal. Acrocyanosis is a bluish discoloration of the hands and feet caused by poor circulation. Newborns normally have acrocyanosis for the first few days of life because they are adjusting to the temperature outside the womb.
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