An older adult is admitted to the hospital. The patient's height is 5 feet, 6 Inches (1.68M), and weigh 250 lb. (113.3kg). The nurse calculates the patient's current body mass index (BMI) as: (Round your answer to the nearest whole number.)
41.0
35.5
30.0
40.0
The Correct Answer is D
To calculate the patient's body mass index (BMI), we need to divide the weight (in kilograms) by the square of the height (in meters). Let's convert the height and weight measurements to the appropriate units and perform the calculation:
Height: 5 feet, 6 inches = 5 + (6/12) = 5.5 feet = 1.6764 meters (rounded to four decimal places) Weight: 250 lb. = 113.3 kg
BMI = Weight (kg) / (Height (m))^2
BMI = 113.3 kg / (1.6764 m)^2
BMI ≈ 40.0
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is D
Explanation
To calculate the milliliters per hour (mL/hr) for the IV infusion, you divide the total volume (in milliliters) by the total time (in hours).
In this case, the total volume is 1 liter, which is equal to 1000 milliliters, and the total time is 6 hours.
So, you divide 1000 mL by 6 hours:
1000 mL / 6 hours = 166.67 mL/hr
Rounding off, the nurse will program the IV infusion device to infuse at approximately 167 mL/hr.
Correct Answer is C
Explanation
The pH value of 7.5 indicates alkalosis, as it is above the normal range of 7.35-7.45. The elevated bicarbonate (HCO3-) level of 34 mmol/L suggests metabolic alkalosis, as it is higher than the normal range of 22-28 mmol/L. The PaCO2 level of 40 mm Hg falls within the normal range of 35-45 mm Hg.
In this case, the primary disturbance is metabolic alkalosis, which is likely caused by vomiting leading to excessive loss of gastric acid (hydrogen ions) and chloride ions from the stomach. This loss of acid and chloride results in an imbalance of electrolytes and an increase in bicarbonate levels, leading to metabolic alkalosis.
The arterial blood gas results do not indicate any compensation. Compensation occurs when the body attempts to restore the pH balance by adjusting the respiratory or metabolic systems. In this case, there is no compensation observed because the PaCO2 level is within the normal range and not significantly altered.
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