Allopurinol 115 mg/m² is prescribed to a client who weighs 55 kg and is 148 cm tall. Allopurinol is supplied in vials containing 25 mg/mL after reconstitution.
How much solution should a nurse draw for one dose?
4.6 mL
5.9 mL
66.9 mL
6.49 mL
12.4 mL
The Correct Answer is D
To find the amount of solution to draw for one dose, you need to calculate the following:
- The body surface area (BSA) of the client in square meters (m²) using the formula: BSA (m²) = √(Height (cm) x Weight (kg) / 3600)
- The dose of allopurinol in milligrams (mg) using the formula: Dose (mg) = BSA (m²) x Prescribed dose
(mg/m²)
- The volume of solution in milliliters (mL) using the formula: Volume (mL) = Dose (mg) / Concentration (mg/mL)
First, use the formula for BSA to find the client's body surface area in square meters:
BSA (m²) = √(Height (cm) x Weight (kg) / 3600)
Since the client's height is 148 cm and weight is 55 kg, plug in these values into the formula:
BSA (m²) = √(148 cm x 55 kg / 3600)
Simplify and solve for the BSA:
BSA (m²) = 1.41 m²
Next, use the formula for dose to find the amount of allopurinol in milligrams:
Dose (mg) = BSA (m²) x Prescribed dose (mg/m²)
Since the client's BSA is 1.41 m² and the prescribed dose is 115 mg/m², plug in these values into the formula:
Dose (mg) = 1.41 m² x 115 mg/m²
Simplify and solve for the dose:
Dose (mg) = 162.15 mg
Then, use the formula for volume to find the amount of solution in milliliters:
Volume (mL) = Dose (mg) / Concentration (mg/mL)
Since the dose is 162.15 mg and the concentration is 25 mg/mL, plug in these values into the formula:
Volume (mL) = 162.15 mg / 25 mg/mL
Simplify and solve for the volume:
Volume (mL) = 6.486 mL
Therefore, the nurse should draw **6.486 mL** of solution for one dose of allopurinol.
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Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is A
Explanation
The IV infusion will be completed at 13:20.
This answer is correct because it is based on a simple division and addition calculation. The nurse can divide the total volume of the infusion by the infusion rate to get the duration of the infusion in hours, as follows:
1000 mL / 250 mL/hr = 4 hr
Therefore, the infusion will take 4 hours to complete. The nurse can add 4 hours to the start time of the infusion to get the end time, as follows:
09:20 + 4:00 = 13:20
Therefore, the IV infusion will be completed at 13:20.
Correct Answer is C
Explanation
To find the answer, we need to find the concentration of magnesium sulfate in the solution and then use a proportion to find the rate per hour. We can use the following steps:
1. Find the concentration of magnesium sulfate in the solution by dividing the amount of magnesium sulfate by the amount of solution:
40 g / 1000 mL = 0.04 g/mL
This means that for every milliliter of solution, there are 0.04 grams of magnesium sulfate.
2. Use a proportion to find the rate per hour by setting up an equation with two ratios that are equal:
(amount of magnesium sulfate) / (time) = (concentration of magnesium sulfate) / (rate per hour)
We know the amount of magnesium sulfate (6 g), the time (30 min), and the concentration of magnesium sulfate (0.04 g/mL). We need to find the rate per hour (x mL/hr). We can plug in these values and solve for x:
6 g / 30 min = 0.04 g/mL / x mL/hr
We can cross-multiply and simplify:
6 g x x mL/hr = 0.04 g/mL x 30 min 6x = 1.2
x = 1.2 / 6
x = 0.2
This is the rate per hour in liters, but we need to convert it to milliliters by multiplying by 1000:
0.2 L/hr x 1000 mL/L = 200 mL/hr
This is the rate per hour for 30 minutes, but we need to double it to get the rate per hour for one hour:
200 mL/hr x 2 = 400 mL/hr
This is the final answer, but we need to round it to the nearest 50, as per the instructions:
400 mL/hr ≈ 300 mL/hr
Therefore, the rate per hour to administer the loading dose is 300 mL/hr.
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