A patient is receiving an IV of esmolol 2.5 grams in 250 mL of D5W (dextrose 5% in water) infusing at 200 micrograms/kilogram/minute. The patient weighs 110 lb. What rate (in mL/hr) should the nurse program into the IV pump to deliver this dose?
45 mL/hr
60 mL/hr
75 mL/hr
90 mL/hr
The Correct Answer is C
To calculate the rate (in mL/hr) at which the IV pump should be programmed to deliver the dose of esmolol, we can use the following formula:
Rate (mL/hr) = (Dose × Patient weight × 60) / (Concentration × Time)
Given:
Dose = 2.5 grams Patient weight = 110 lb Concentration = 250 mL
Time = 1 hour (since the dose is given per hour)
Converting the patient's weight from pounds to kilograms:
Patient weight = 110 lb ÷ 2.2046 = 49.9 kg
Substituting the values into the formula:
Rate (mL/hr) = (2.5 g × 49.9 kg × 60) / (250 mL × 1)
Simplifying the equation:
Rate (mL/hr) = (2.5 × 49.9 × 60) / 250
Rate (mL/hr) = 74.85
Rounding to the nearest whole number, the nurse should program the IV pump to deliver 75 mL/hr.
Therefore, the correct answer is c. 75 mL/hr.
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Related Questions
Correct Answer is B
Explanation
The nurse should administer 1050 mg of medication to achieve the total prescribed dose.
This answer is correct because it is based on a simple multiplication calculation. The nurse can multiply the prescribed dose per kilogram by the weight of the client in kilograms to get the total dose in milligrams, as follows:
25 mg/kg x 42 kg = 1050 mg
Therefore, the nurse should administer 1050 mg of medication to the client.
Correct Answer is C
Explanation
The nurse should administer 12.5 mL of amoxicillin oral suspension.
This answer is correct because it is based on a simple ratio and proportion calculation. The nurse can set up a proportion as follows:
200 mg / 5 mL = 500 mg / x mL
Cross-multiplying and solving for x gives:
x = 12.5 mL
Therefore, the nurse should administer 12.5 mL of amoxicillin oral suspension to deliver 500 mg of the medication to the patient.
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