A patient is receiving an IV of esmolol 2.5 grams in 250 mL of D5W (dextrose 5% in water) infusing at 200 micrograms/kilogram/minute. The patient weighs 110 lb. What rate (in mL/hr) should the nurse program into the IV pump to deliver this dose?
45 mL/hr
60 mL/hr
75 mL/hr
90 mL/hr
The Correct Answer is B
Step 1 is Convert pounds to kilograms 110 lb ÷ 2.2 = 50 kg
Step 2 is Calculate dose in micrograms per minute 50 kg × 200 micrograms = 10,000 micrograms/min
Step 3 is Convert micrograms to milligrams 10,000 micrograms ÷ 1000 = 10 mg/min
Step 4 is Convert mg/min to mg/hr 10 mg × 60 = 600 mg/hr
Step 5 is Determine concentration of esmolol in mg/mL 2.5 grams × 1000 = 2500 mg 2500 mg ÷ 250 mL = 10 mg/mL
Step 6 is Calculate infusion rate in mL/hr 600 mg/hr ÷ 10 mg/mL = 60 mL/hr
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Related Questions
Correct Answer is C
Explanation
The nurse should administer 1 mL per dose to the patient.
This answer is correct because it is based on a simple ratio and proportion calculation. The nurse can set up a proportion as follows:
30 mg / 1 mL = 30 mg / x mL
Cross-multiplying and solving for x gives:
x = 1 mL
Therefore, the nurse should administer 1 mL of Toradol injection to deliver 30 mg of the medication to the patient.
Correct Answer is B
Explanation
To find the flow rate in mL/hr, you need to use the formula for infusion rate:
Infusion rate (mL/h) = Total volume (mL) / Time (h)
Since the total volume is 2.5 L and the time is 15 hours, plug in these values into the formula:
Infusion rate (mL/h) = 2.5 L / 15 h
However, before you can simplify and solve for the infusion rate, you need to convert the volume from liters to milliliters by multiplying by 1000:
Infusion rate (mL/h) = 2500 mL / 15 h
Simplify and solve for the infusion rate:
Infusion rate (mL/h) = 166.67 mL/h
Therefore, the flow rate for continuous infusion is **166.67 mL/h**.
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