A patient is receiving an IV of esmolol 2.5 grams in 250 mL of D5W (dextrose 5% in water) infusing at 200 micrograms/kilogram/minute. The patient weighs 110 lb. What rate (in mL/hr) should the nurse program into the IV pump to deliver this dose?
45 mL/hr
60 mL/hr
75 mL/hr
90 mL/hr
The Correct Answer is B
Step 1 is Convert pounds to kilograms 110 lb ÷ 2.2 = 50 kg
Step 2 is Calculate dose in micrograms per minute 50 kg × 200 micrograms = 10,000 micrograms/min
Step 3 is Convert micrograms to milligrams 10,000 micrograms ÷ 1000 = 10 mg/min
Step 4 is Convert mg/min to mg/hr 10 mg × 60 = 600 mg/hr
Step 5 is Determine concentration of esmolol in mg/mL 2.5 grams × 1000 = 2500 mg 2500 mg ÷ 250 mL = 10 mg/mL
Step 6 is Calculate infusion rate in mL/hr 600 mg/hr ÷ 10 mg/mL = 60 mL/hr
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is B
Explanation
The correct angle for giving an intradermal injection is **10 to 15 degrees**. This angle allows the needle to enter the dermis, which is the layer of skin just below the epidermis. The needle should be inserted almost flat against the patient's skin, with the bevel side up. A small blister or bleb should form under the skin after injecting the medication.

Correct Answer is A
Explanation
The amount of ampicillin in one dose is 390 mg.
This answer is correct because it is based on a series of multiplication and division calculations. The nurse should follow these steps to determine the amount of ampicillin in one dose:
1) Multiply the prescribed dose per kilogram per day by the child's weight in kilograms to get the total dose per day in milligrams, as follows:
150 mg/kg/day x 10.4 kg = 1560 mg/day
Therefore, the child needs 1560 mg of ampicillin per day.
2) Divide the total dose per day by the number of doses per day to get the amount of each dose in milligrams, as follows:
1560 mg/day / 4 doses/day = 390 mg/dose
Therefore, the amount of ampicillin in one dose is 390 mg.
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