A vial contains 1.5 g of ceftriaxone. The final concentration after adding diluent should be 600 mg/3 mL. How much diluent should a nurse add to achieve this concentration?
0.0075 mL
1.2 mL
7.5 mL
1800 mL
The Correct Answer is C
To calculate the amount of diluent that should be added, we need to first calculate the volume of the final solution. .
The final concentration of ceftriaxone should be 600 mg/3 mL, which is the same as 200 mg/mL. .
If we have 1.5 g (or 1500 mg) of ceftriaxone, we can divide this by the desired concentration to get the total volume of the final solution:.
1500 mg ÷ 200 mg/mL = 7.5 mL.
So, the total volume of the final solution should be 7.5 mL. .
To calculate the amount of diluent needed, we need to subtract the volume of the ceftriaxone from the total volume of the final solution:.
7.5 mL - 0.00 mL = 7.5 mL.
Therefore, a nurse should add 7.5 mL of diluent to the vial containing 1.5 g of ceftriaxone to achieve a final concentration of 600 mg/3 mL.

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Related Questions
Correct Answer is B
Explanation
To calculate the flow rate in mL/hr for a continuous infusion, we need to divide the total volume to be infused by the total time of infusion, and then convert the units as necessary.
In this case, the total volume is 2.5 L, which is equivalent to 2500 mL (1 L = 1000 mL), and the total time is 15 hours.
Flow rate = Total volume to be infused / Total time of infusion Flow rate = 2500 mL / 15 hours
Flow rate = 166.67 mL/hr
Therefore, the flow rate for continuous infusion of 0.9% sodium chloride solution in this case is 166.67 mL/hr.
Correct Answer is C
Explanation
To calculate the total infusion time, we need to divide the total volume to be infused by the infusion rate:.
Total infusion time = Total volume to be infused / Infusion rate.
In this case, the total volume to be infused is 1000 mL, and the infusion rate is 250 mL/hr:.
Total infusion time = 1000 mL / 250 mL/hr. Total infusion time = 4 hours.
Therefore, the infusion will be completed 4 hours after it was started at 09:20, which would be at 13:20.
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