A nurse is providing phone advice for a client who is pregnant.
Complete the following sentence by using the copy pasting from the list of options.
The client is at risk for experiencingelectrolyte imbalancedue to the
The Correct Answer is {"dropdown-group-1":"C"}
Electrolyte imbalance in pregnant clients is often associated with conditions that lead to dehydration and nutritional deficiencies. In this scenario, the key indicators are persistent nausea and significant weight loss.
- Persistent nausea can lead to reduced food and fluid intake. This condition, especially if prolonged, can cause dehydration and electrolyte imbalances due to the loss of essential minerals and nutrients that are not being replenished due to inadequate dietary intake.
- Significant weight loss, particularly the amount described in the scenario (6.8 kg or 15 lb), is a clear sign of inadequate nutritional intake and can further exacerbate the risk of electrolyte imbalance. It indicates that the body is not receiving enough nutrients, which is crucial for maintaining electrolyte balance.
The other options, while related to diet and fluid intake, are more specific to the client's eating habits and do not directly point to the primary cause of potential electrolyte imbalance in the context of this scenario. Therefore, the most comprehensive and medically relevant choice is (A) Persistent nausea and significant weight loss.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
- A. Incorrect. The nurse should assess the client's IV site every hour to prevent infection and phlebitis.
- B. Incorrect. The nurse should check the client's WBC count every day to monitor for signs of infection or bone marrow suppression.
- C. Correct. The nurse should monitor the client's mouth every 8 hr for signs of oral candidiasis, which is a common fungal infection in immunosuppressed clients.\
- D. Incorrect. The nurse should change the client's IV tubing every 24 hr to reduce the risk of bacterial contamination.
Correct Answer is ["18"]
Explanation
The client weighs 198 lb, which is equivalent to (198 ÷ 2.2 = 90kg.
Therefore, the amount of mannitol for the test dose is 0.2 g/kg x 90 kg = 18 g. The nurse should administer 18 g of mannitol IV bolus over 5 min as a test dose to the client who has severe oliguria.
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