A nurse is caring for a female client in the emergency department who reports shortness of breath and pain in the lung area. She states that she started taking birth control pills 3 weeks ago and that she smokes. Her heart rate is 110/min, respiratory rate 40/min, and blood pressure 140/80 mm Hg. Her arterial blood gases are pH 7.50, PaCO2 29 mm Hg, PaO2 60 mm Hg, HCO3 20 mEq/L, and SaO2 86%. Which of the following is the priority nursing intervention?
Prepare to administer a sedative.
Prepare for mechanical ventilation.
Massage the calf area for tenderness.
Assess for indications of pulmonary embolism.
The Correct Answer is D
The correct answer is d. Assess for indications of pulmonary embolism.
Choice A rationale:
Administering a sedative is not appropriate as the priority intervention. Sedatives can depress respiratory function, which is already compromised in this patient.
Choice B rationale:
Preparing for mechanical ventilation might be necessary if the patient’s condition worsens, but it is not the immediate priority. The priority is to identify the underlying cause of the symptoms.
Choice C rationale:
Massaging the calf area for tenderness is not relevant in this context. While calf tenderness can be a sign of deep vein thrombosis (DVT), which can lead to pulmonary embolism, the immediate priority is to assess for pulmonary embolism directly.
Choice D rationale:
Assessing for indications of pulmonary embolism is the priority because the patient’s symptoms (shortness of breath, chest pain, recent use of birth control pills, smoking history, and abnormal ABG values) strongly suggest a pulmonary embolism. Early identification and treatment are crucial to prevent further complications.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is B
Explanation
Metabolic alkalosis.
Choice A rationale:
The given blood gas results show a pH of 7.53, which is alkaline (above the normal range of
7.35 to 7.45), and a high bicarbonate level of 36 mEq/L (normal range is 22 to 26 mEq/L). This combination indicates metabolic alkalosis, a condition where there is an excessive accumulation of bicarbonate in the blood, leading to increased pH.
Choice B rationale:
Metabolic alkalosis is characterized by increased blood bicarbonate levels, which can occur due to conditions like vomiting, diuretic use, or excessive ingestion of bicarbonate-containing substances. It results in symptoms such as muscle twitching, tetany, and respiratory depression.
Choice C rationale:
Respiratory alkalosis is characterized by an elevated blood pH and low carbon dioxide levels (hypocapnia). However, the bicarbonate level is not directly related to respiratory alkalosis, making this choice incorrect based on the given information.
Choice D rationale:
Metabolic acidosis is characterized by a decreased blood pH and low bicarbonate levels. The presented blood gas results show an alkaline pH and high bicarbonate, making this choice incorrect.
Correct Answer is ["A","C","D"]
Explanation
A, C, and D.
Choice A rationale:
The administration of sodium bicarbonate helps to correct acidosis, which can occur in chronic renal failure due to the accumulation of metabolic waste products in the absence of effective kidney function.
Choice C rationale:
Sodium polystyrene sulfonate (Kayexalate) is used to treat hyperkalemia, which is common in chronic renal failure due to impaired potassium excretion by the kidneys.
Choice D rationale:
Insulin can be prescribed to treat hyperkalemia by promoting the uptake of potassium into cells, thereby reducing the serum potassium level. Choice B and E rationale: Dextrose 10% and furosemide (Lasix) are not appropriate treatments for hyperkalemia. Dextrose 10% is asugar solution and does not impact potassium levels, while furosemide is a loop diuretic that primarily affects sodium and water excretion, not potassium.
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