Related Questions

Correct Answer is A

Explanation

Choice A Reason: This choice is correct because respiratory acidosis is a condition in which the lungs cannot eliminate enough carbon dioxide (CO2) from the blood, resulting in a high level of CO2 (PaCO2) and a low level of pH. A normal PaCO2 range is 35 to 45 mm Hg, so a value of 50 mm Hg indicates respiratory acidosis.

Choice B Reason: This choice is incorrect because HCO3 (bicarbonate) is a base that helps to buffer the excess acid in the blood. In respiratory acidosis, the kidneys try to compensate by retaining more HCO3 and excreting more hydrogen ions. Therefore, a high level of HCO3 (above 26 mEq/L) would indicate a chronic or compensated respiratory acidosis, not an acute or uncompensated one.

Choice C Reason: This choice is incorrect because pH is a measure of the acidity or alkalinity of the blood. A normal pH range is 7.35 to 7.45, so a value of 7.45 indicates a neutral or slightly alkaline blood, not an acidic one. A low pH (below 7.35) would indicate respiratory acidosis.

Choice D Reason: This choice is incorrect because potassium is an electrolyte that helps to regulate the nerve and muscle function, as well as the fluid balance in the body. In respiratory acidosis, the increased hydrogen ions in the blood may shift into the cells in exchange for potassium, resulting in a high level of potassium (hyperkalemia).

Therefore, a low level of potassium (below 3.5 mEq/L) would indicate hypokalemia, not respiratory acidosis.

Correct Answer is A

Explanation

Choice A Reason: To calculate the total body surface area (TBSA) affected by burns using the Rule of Nines, the body is divided into sections, each representing a percentage of TBSA:

  • Front of one leg = 9%
  • Back of one leg = 9%
  • Front of one arm = 4.5%
  • Back of one arm = 4.5%

Now for the calculation:

  1. Both legs (front and back):

    • Front of both legs = 9% × 2 = 18%
    • Back of both legs = 9% × 2 = 18%
    • Total for both legs = 18% + 18% = 36%
  2. Both arms (front and back):

    • Front of both arms = 4.5% × 2 = 9%
    • Back of both arms = 4.5% × 2 = 9%
    • Total for both arms = 9% + 9% = 18%
  3. Total TBSA:

    • Legs (36%) + Arms (18%) = 54%

The nurse should document burns to 54% of the client's total body surface area (TBSA).

Choice B Reason:This choice is incorrect because it uses the original rule of nines for adults, not children. It also does not account for the depth and degree of the burns.

Choice C Reason: This choice is incorrect because it uses the original rule of nines for adults, not children. It also does not account for the depth and degree of the burns.

Choice D Reason: This choice is incorrect because it uses a random percentage that does not correspond to any rule or calculation.

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