A nurse is caring for a child who has tinea pedis. The child’s parent asks the nurse what this infection is commonly called. The nurse should respond with which of the following common names?
Shingles
Athlete’s foot
Fever blister
Pinworms
The Correct Answer is B
Choice A rationale
Shingles, also known as herpes zoster, is a viral infection that causes a painful rash and is caused by the varicella-zoster virus, the same virus that causes chickenpox.
Choice B rationale
Tinea pedis is a foot infection due to a dermatophyte fungus. It is the most common dermatophyte infection and is particularly prevalent in hot, tropical, urban environments. Interdigital involvement is most commonly seen (this presentation is also known as athlete’s foot, although some people use the term for any kind of tinea pedis).
Choice C rationale
Fever blister, also known as cold sores, are caused by the herpes simplex virus. They are small, fluid-filled blisters that develop on the lips or around the mouth.
Choice D rationale
Pinworms are a type of parasite that lives in the lower intestine of humans. They are tiny, narrow worms. They are white and less than a half-inch long.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is A
Explanation
Choice A rationale
A urine specific gravity of 1.034 is higher than the normal range (1.002-1.030), indicating that the urine is more concentrated due to a lack of hydration.
Choice B rationale
A bounding pulse is not typically associated with dehydration. Dehydration more commonly results in a weak, rapid pulse.
Choice C rationale
A blood pressure reading of 46/94 mm Hg is not indicative of dehydration. Dehydration often leads to low blood pressure.
Choice D rationale
Distended neck veins are not a typical sign of dehydration. Dehydration can lead to decreased blood volume, which would not cause distension of the neck veins.
Correct Answer is C
Explanation
The correct answer is Choice C.
Step 1: Convert the child’s weight from lbs to kg.
Since 1 lb is approximately 0.45 kg, a child who weighs 6 lbs weighs approximately 2.72 kg (6 lbs × 0.45 =2.72 kg). Step 2: Calculate the total daily dose of Ampicillin. The total daily dose is 50 mg/kg/day, so for a child who weighs 2.72 kg, the total daily dose would be approximately 136 mg (50 mg/kg/day × 2.72 kg = 136 mg/day). Step 3: Since the total daily dose is divided into q hr doses (4 doses per day), each dose would be approximately 34 mg (136 mg/day ÷ 4 doses/day = 34 mg/dose). So, the child will receive approximately 34 mg of Ampicillin with each dose.
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