A nurse is assessing a client who has pneumonia. Which of the following manifestations should the nurse expect?
Crackles.
Crepitus.
Stridor.
Decreased fremitus.
The Correct Answer is A
Choice A rationale:
Crackles are adventitious lung sounds that can be heard on auscultation and are commonly associated with pneumonia. They are caused by the movement of air through fluid-filled or collapsed alveoli, indicating inflammation and infection in the lungs.
Choice B rationale:
Crepitus is a different respiratory finding and is not typically associated with pneumonia. Crepitus is a crackling or grating sensation that can be felt under the skin, often caused by subcutaneous emphysema or gas trapped in the tissues, not within the lungs.
Choice C rationale:
Stridor is a harsh, high-pitched sound heard during inspiration and is usually indicative of upper airway obstruction, not pneumonia. It can be caused by conditions such as croup or anaphylaxis.
Choice D rationale:
Decreased fremitus is not a specific manifestation of pneumonia. Fremitus is the vibration felt when the patient speaks and is transmitted through the chest wall. In pneumonia, increased fremitus may be observed due to the consolidation of lung tissue with fluid or pus, not decreased fremitus.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is A
Explanation
Choice A rationale:
The client's ABG values show a pH of 7.48, PCO2 of 30 mm Hg, HCO3 of 24 mEq/L, and PaO2 of 85 mm Hg. The elevated pH and decreased PCO2 (respiratory component) suggest respiratory alkalosis. Respiratory alkalosis occurs when there is excessive ventilation, leading to a decrease in carbon dioxide levels (hypocapnia) and subsequent alkalosis.
Choice B rationale:
Respiratory acidosis is characterized by an elevated PCO2 and decreased pH. In this case, the client's PCO2 is decreased, indicating respiratory alkalosis rather than respiratory acidosis.
Choice C rationale:
Metabolic alkalosis is characterized by an elevated HCO3 (bicarbonate) level and an increased pH. The client's HCO3 level is within the normal range, making metabolic alkalosis an incorrect identification.
Choice D rationale:
Metabolic acidosis is characterized by a decreased HCO3 level and a decreased pH. The client's HCO3 level is within the normal range, ruling out metabolic acidosis as the acid-base imbalance in this case.
Correct Answer is ["A","D"]
Explanation
Choice A rationale:
Prolonged sun exposure is a risk factor for osteoporosis because it can lead to vitamin D deficiency. Vitamin D is essential for calcium absorption, and low levels of vitamin D can contribute to reduced bone density and increased risk of fractures.
Choice B rationale:
Reduced intake of vitamin E is not a well-established risk factor for osteoporosis. Vitamin E is an antioxidant and plays a role in various bodily processes, but its association with osteoporosis is not supported by strong evidence.
Choice C rationale:
Drinking one glass of wine per day is not a risk factor for osteoporosis. In fact, moderate alcohol consumption has been suggested to have a protective effect on bone density in some studies.
Choice D rationale:
Exposure to second-hand tobacco smoke is a risk factor for osteoporosis. Smoking and exposure to tobacco smoke have been linked to decreased bone density and increased risk of fractures, making this an important point to include in the teaching.
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