A client with pneumonia is receiving a secondary infusion of azithromycin 500 mg in 250 mL of normal saline (NS) to be infused in 90 minutes. How many mL/hour should the nurse program the infusion pump?
The Correct Answer is ["167"]
The client with pneumonia is receiving a secondary infusion of azithromycin 500 mg in 250 mL of normal saline (NS) to be infused in 90 minutes.
To calculate the infusion rate in mL/hour, we need to divide the total volume of the infusion (250 mL) by the infusion time in hours (90 minutes / 60 minutes/hour = 1.5 hours).
The nurse should program the infusion pump to deliver 167 mL/hour (250 mL / 1.5 hours).
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Related Questions
Correct Answer is ["1.85"]
Explanation
The healthcare provider prescribes lorazepam at a dose of 50 mcg/kg intramuscularly 2 hours before a scheduled procedure for a client who weighs 74 kg.
The client should receive 3700 mcg of lorazepam (50 mcg/kg * 74 kg). Since 1 mg is equivalent to 1000 mcg, 3700 mcg is equivalent to 3.7 mg.
The medication is available in a 2 mg/mL vial, so the nurse should administer 1.85 mL of medication (3.7 mg / 2 mg/mL).
Correct Answer is ["9"]
Explanation
To calculate the drop rate in gtts/minute, we can use the following formula:
Drop rate (gtts/minute) = (Volume (mL) x Drop factor) / Time (minutes)
Volume to be infused: 55 mL/hour
Drop factor: 10 gtt/mL
Time: 60 minutes/hour
(55 mL x 10 gtt/mL) / 60 minutes = 9.17 gtts/minute
We can round this value to the nearest whole number to get 9gtts/min
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