A client is admitted to the unit at 1500. The provider has prescribed a full liquid diet for the client. The client ingests the following from 1600 to 2115:
- Chicken broth: 120 mL
- Tea: 4 ounces
- Ice cream: 1 cup
- Soda: 6 ounce can
- Water: 550 mL
- Ice chips: 500 mL
The client voids the following:
- At 1530: 400 mL
- At 2015: 775 mL
- At 2245: 200 mL
Calculate the cumulative fluid intake for the 3 p.m. to 11 p.m. shift. Note that intake and output is calculated at 2200 for the 3 p.m.-11 p.m. shift. (Round to the nearest whole number, use a preceding zero, do not use trailing zeros)
The Correct Answer is ["1705"]
To calculate the cumulative fluid intake for the client from 3 p.m. to 11 p.m., convert all measurements to the same unit and then sum them up.
First, convert ounces to milliliters (1 ounce = 29.5735 ml). The tea is 4 ounces, which is approximately 118 ml, and the soda is 6 ounces, approximately 177 ml.
Add all the liquid intake: chicken broth (120 ml) + tea (118 ml) + ice cream (assumed to be 240 ml for 1 cup) + soda (177 ml) + water (550 ml) + half the volume of ice chips (as half the volume of ice chips is water, so 250 ml). The total intake is 120 + 118 + 240 + 177 + 550 + 500= 1705 ml.
Since the intake and output are calculated at 2200, and the client has not consumed anything after 2115, the cumulative fluid intake for the shift is 1705 ml.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
C. If the stressor persists for a prolonged period and the body is unable to adapt or cope effectively, it enters the exhaustion phase. During this phase, the body's resources become depleted. The client experiences decreased energy, reduced ability to cope with stress, and may develop stress-related illnesses or complications.
A. It is characterized by the body's immediate response to a stressor, where physiological changes occur such as increased heart rate, heightened senses, and activation of the fight-or-flight response.
B. After the initial alarm reaction, if the stressor persists, the body enters the resistance phase. In this phase, physiological changes stabilize as the body attempts to cope with the stressor.
D. This phase occurs if the stressor is removed or successfully managed, allowing the body to recover and return to a state of homeostasis. During recovery, the body repairs any damage caused by the stress response and replenishes its energy and resources.
Correct Answer is B
Explanation
B. pH 7.25, PaCO2 61, HCO3 26
pH is decreased (acidosis).
PaCO2 is elevated (61 mmHg), indicating respiratory acidosis (increased CO2 retention). HCO3 is slightly elevated (26 mEq/L), compensating for the respiratory acidosis.
A. pH 7.45, PaCO2 35, HCO3 22
pH is within normal range (7.35-7.45).
PaCO2 is slightly lower than normal (35 mmHg), indicating mild respiratory alkalosis. HCO3 (bicarbonate) is within normal range (22 mEq/L).
C. pH 7.23, PaCO2 27, HCO3 25
pH is decreased (acidosis).
PaCO2 is lower than normal (27 mmHg), indicating respiratory alkalosis (which is unlikely in the context of morphine overdose with hypoventilation).
HCO3 is within normal range (25 mEq/L).
D. pH 7.54, PaCO2 59, HCO3 26
pH is increased (alkalosis).
PaCO2 is elevated (59 mmHg), indicating respiratory acidosis (consistent with hypoventilation). HCO3 is slightly elevated (26 mEq/L), compensating for the respiratory acidosis.
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