Which change occurs first, making patients susceptible to coronary artery disease?
Formation of thrombus in the coronary artery.
Formation of fibrous plaque in the endothelium.
Reduction of blood flow through the coronary arteries.
Development of fatty streaks in the smooth muscles of the endothelium.
The Correct Answer is D
Choice A rationale:
Thrombus formation is a later stage event in coronary artery disease (CAD) and occurs after the development of fatty streaks. Thrombus formation usually happens due to the rupture of atherosclerotic plaques, leading to platelet aggregation and clot formation.
Choice B rationale:
Formation of fibrous plaque in the endothelium is a progression that occurs after the initial development of fatty streaks. Fibrous plaques are formed as a response to the inflammation caused by fatty deposits. They are more stable than fatty streaks but can still lead to narrowing of the arteries.
Choice C rationale:
Reduction of blood flow through the coronary arteries is a consequence of atherosclerosis, which occurs after the initial development of fatty streaks. As the fatty deposits accumulate, they narrow the arteries, leading to reduced blood flow. However, this is not the initial change that makes patients susceptible to CAD.
Choice D rationale:
Development of fatty streaks in the smooth muscles of the endothelium is the initial change that occurs in the development of atherosclerosis, making patients susceptible to coronary artery disease. Fatty streaks are composed of lipid-laden macrophages and smooth muscle cells. Over time, these fatty streaks can progress into fibrous plaques and eventually lead to complications such as thrombus formation and reduced blood flow.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
Choice A rationale:
Metabolic acidosis is characterized by low blood pH and low bicarbonate ion levels. In this case, the patient has a high bicarbonate ion level (25 mEq/L), indicating a compensatory response to respiratory acidosis. Metabolic alkalosis, on the other hand, would present with high pH and high bicarbonate ion levels.
Choice B rationale:
Metabolic alkalosis is characterized by high blood pH and high bicarbonate ion levels. The patient's bicarbonate ion level (25 mEq/L) is within the normal range, and the low pH and high PaCO2 (49 mm Hg) indicate respiratory acidosis, not metabolic alkalosis.
Choice C rationale:
Respiratory acidosis is characterized by low blood pH and high partial pressure of carbon dioxide (PaCO2) levels. In this case, the patient has a low pH (7.29) and elevated PaCO2 (49 mm Hg), indicating respiratory acidosis. The elevated bicarbonate ion level (25 mEq/L) is a compensatory response. Respiratory alkalosis would present with high pH and low PaCO2 levels.
Choice D rationale:
Respiratory alkalosis is characterized by high blood pH and low PaCO2 levels. The patient's PaCO2 level is elevated (49 mm Hg), indicating respiratory acidosis, not alkalosis. The low pH (7.29) further supports the diagnosis of respiratory acidosis.
Correct Answer is C
Explanation
The correct answer is choice C. Uses an alcohol-based mouthwash twice a day.
Choice A rationale:
Drinking 14 glasses of water daily is generally beneficial as it helps maintain hydration and supports overall health. However, it is important to balance fluid intake to avoid overhydration.
Choice B rationale:
Shaving with an electric razor is recommended for patients with thrombocytopenia because it reduces the risk of cuts and bleeding compared to using a traditional razor.
Choice C rationale:
Using an alcohol-based mouthwash can cause dryness and irritation of the oral mucosa, which can lead to bleeding, especially in patients with thrombocytopenia. It is better to use a non-alcoholic mouthwash.
Choice D rationale:
Brushing teeth with a soft-bristle toothbrush is advised to minimize the risk of gum bleeding and maintain oral hygiene.
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