When a pregnant patient has genital herpes, for which complication is the patient at higher risk than the general population?
Forceps-assisted second stage of labor.
Precipitous delivery.
Prolonged first phase of labor.
Cesarean delivery.
The Correct Answer is D
The correct answer is choice D. Cesarean delivery. A pregnant patient with genital herpes is at higher risk of transmitting the infection to the baby during vaginal delivery, especially if there is an active outbreak near the time of birth. This can cause serious complications for the baby, such as brain damage, eye problems, or even death. Therefore, a cesarean delivery is recommended to avoid contact between the baby and the genital lesions.
Choice A is wrong because forceps-assisted second stage of labor is not a complication of genital herpes.
It is a method of assisted delivery that may be used for various reasons, such as fetal distress, maternal exhaustion, or abnormal presentation.
Choice B is wrong because precipitous delivery, which means a very fast labor and delivery, is not a complication of genital herpes.
It may be caused by factors such as multiparity, strong contractions, or previous rapid deliveries.
Choice C is wrong because prolonged first phase of labor, which means a slow dilation of the cervix, is not a complication of genital herpes.
It may be caused by factors such as ineffective contractions, large fetal size, or malposition.
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Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
The correct answer is choice C: Related to the influence of maternal hormones.This is because breast milk contains many hormones that pass into it from the mother’s body, such as prolactin, thyroid hormones, and estrogen.
These hormones can affect the baby’s growth and development, and sometimes cause temporary breast enlargement and milk secretion in newborns of both sexes.This is called neonatal galactorrhea or “witch’s milk” and it is harmless and usually resolves within a few weeks
Choice A is wrong because neonatal galactorrhea is not a symptom of an endocrine disorder.It is a normal physiological response to maternal hormones that cross the placenta during pregnancy and are present in breast milk
Choice B is wrong because neonatal galactorrhea is not related to the need for chromosomal determination of gender identity.Gender identity is determined by a complex interaction of genetic, hormonal, and environmental factors, and it is not influenced by breast milk production in newborns
Choice D is wrong because neonatal galactorrhea is not a symptom of an abnormal proliferation of mammary alveoli.
Mammary alveoli are the milk-producing cells in the breast, and they are stimulated by prolactin to secrete milk.Neonatal galactorrhea does not indicate any abnormality in the structure or function of the mammary glands
Correct Answer is D
Explanation
The correct answer is choice D. Insufficient relaxation of the uterus between contractions.This is also known astachysystoleorhyperstimulation, which can cause fetal distress and uterine rupture.Oxytocin is a hormone that stimulates uterine contractions, but it can also cause them to be too strong or too frequent if given in high doses or for too long.
Choice A is wrong because oxytocin does not decrease body temperature.
Choice B is wrong because oxytocin does not cause maternal cardiac arrhythmias.
Choice C is wrong because oxytocin does not cause urinary retention.
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