When a pregnant patient has genital herpes, for which complication is the patient at higher risk than the general population?
Forceps-assisted second stage of labor.
Precipitous delivery.
Prolonged first phase of labor.
Cesarean delivery.
The Correct Answer is D
The correct answer is choice D. Cesarean delivery. A pregnant patient with genital herpes is at higher risk of transmitting the infection to the baby during vaginal delivery, especially if there is an active outbreak near the time of birth. This can cause serious complications for the baby, such as brain damage, eye problems, or even death. Therefore, a cesarean delivery is recommended to avoid contact between the baby and the genital lesions.
Choice A is wrong because forceps-assisted second stage of labor is not a complication of genital herpes.
It is a method of assisted delivery that may be used for various reasons, such as fetal distress, maternal exhaustion, or abnormal presentation.
Choice B is wrong because precipitous delivery, which means a very fast labor and delivery, is not a complication of genital herpes.
It may be caused by factors such as multiparity, strong contractions, or previous rapid deliveries.
Choice C is wrong because prolonged first phase of labor, which means a slow dilation of the cervix, is not a complication of genital herpes.
It may be caused by factors such as ineffective contractions, large fetal size, or malposition.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is D
Explanation
The correct answer is choice D. Insufficient relaxation of the uterus between contractions.This is also known astachysystoleorhyperstimulation, which can cause fetal distress and uterine rupture.Oxytocin is a hormone that stimulates uterine contractions, but it can also cause them to be too strong or too frequent if given in high doses or for too long.
Choice A is wrong because oxytocin does not decrease body temperature.
Choice B is wrong because oxytocin does not cause maternal cardiac arrhythmias.
Choice C is wrong because oxytocin does not cause urinary retention.
Correct Answer is D
Explanation
he correct answer is choice D. Keep the infant well hydrated.This is because phototherapy can cause dehydration due to increased insensible water loss from the skin.Hydration helps the infant excrete bilirubin in urine and stool.
Choice A is wrong because elevating the head of the infant’s crib does not affect bilirubin levels or phototherapy effectiveness.
Choice B is wrong because applying a water-soluble ointment to the infant’s eyes can interfere with eye protection and cause eye irritation.The infant’s eyes should be covered with opaque patches or goggles during phototherapy to prevent eye damage.
Choice C is wrong because dressing the infant in a long-sleeved shirt reduces the amount of skin exposed to light and decreases the efficacy of phototherapy.The infant should be undressed except for a diaper and eye protection during phototherapy.
Normal ranges for bilirubin levels vary depending on the age of the infant, the type of jaundice, and the method of measurement.Generally, bilirubin levels above 25 mg/dL are considered dangerous and require urgent treatment.
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