When a pregnant patient has genital herpes, for which complication is the patient at higher risk than the general population?
Forceps-assisted second stage of labor.
Precipitous delivery.
Prolonged first phase of labor.
Cesarean delivery.
The Correct Answer is D
The correct answer is choice D. Cesarean delivery. A pregnant patient with genital herpes is at higher risk of transmitting the infection to the baby during vaginal delivery, especially if there is an active outbreak near the time of birth. This can cause serious complications for the baby, such as brain damage, eye problems, or even death. Therefore, a cesarean delivery is recommended to avoid contact between the baby and the genital lesions.
Choice A is wrong because forceps-assisted second stage of labor is not a complication of genital herpes.
It is a method of assisted delivery that may be used for various reasons, such as fetal distress, maternal exhaustion, or abnormal presentation.
Choice B is wrong because precipitous delivery, which means a very fast labor and delivery, is not a complication of genital herpes.
It may be caused by factors such as multiparity, strong contractions, or previous rapid deliveries.
Choice C is wrong because prolonged first phase of labor, which means a slow dilation of the cervix, is not a complication of genital herpes.
It may be caused by factors such as ineffective contractions, large fetal size, or malposition.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
The correct answer is choice C. Have a suction catheter available for use at delivery.This is because meconium-stained amniotic fluid indicates that the fetus has passed meconium (first stool) before birth, which can be a sign of fetal distress or hypoxia.Meconium can block the airways and cause breathing problems for the newborn, so suctioning the mouth and nose (or the trachea if needed) is important to prevent meconium aspiration syndrome.
Choice A is wrong because taking the mother’s vital signs every 15 minutes is not a specific intervention for meconium-stained amniotic fluid.
Vital signs should be monitored regularly during labor regardless of the fluid color.
Choice B is wrong because sending a specimen of the fluid to the laboratory for analysis is not a priority action.The color and consistency of the fluid can be observed by the nurse and documented.
The laboratory analysis will not change the immediate management of the newborn.
Choice D is wrong because preparing a slide of the fluid for fern testing is not relevant for meconium-stained amniotic fluid.
Fern testing is used to confirm the rupture of membranes by detecting a fern-like pattern of amniotic fluid under a microscope.It is not useful for assessing the presence or severity of meconium-stained amniotic fluid.
Correct Answer is C
Explanation
The correct answer is choice C. Reminding her that she should be happy that one child survived and is healthy is the least helpful nursing action in supporting the woman as she copes with her loss.
This statement minimizes her grief and implies that she should not feel sad about the deceased twin.
It also disregards her attachment to both babies and her need to mourn the loss of one of them.
Choice A is wrong because offering her the opportunity for counseling to help her grieve is a helpful nursing action that recognizes her emotional distress and provides her with professional support.
Choice B is wrong because encouraging the woman to hold the deceased twin as well as the living twin is a helpful nursing action that allows her to acknowledge and bond with both babies and to create memories that may facilitate healing.
Choice D is wrong because assisting the woman to take pictures of both babies is a helpful nursing action that provides her with tangible mementos of her twins and honors their
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