The nurse is providing care for four patients: Patient A, diagnosed with emphysema and has an oxygen saturation of 94% on room air; Patient B, who is postoperative with a hemoglobin level of 8.2 mg/dL (82 g/L); Patient C, newly admitted with a potassium level of 3.8 mEq/L (3.8 mmol/L); and Patient D, who is scheduled for an appendectomy and has a white blood cell (WBC) count of 14,000 mm² (14 x 10°/L). What action should the nurse take next?
Transfer Patient D to an isolation room 24 hours prior to surgery.
Increase Patient A’s oxygen to 4 L/minute via nasal cannula.
Ensure that there are two units of packed cells available for Patient B.
Request the dietitian to include a banana in Patient C’s breakfast tray.
The Correct Answer is C
Choice A rationale
There is no indication that Patient D, who is scheduled for an appendectomy and has a white blood cell (WBC) count of 14,000 mm² (14 x 10°/L), needs to be transferred to an isolation room 24 hours prior to surgery.
Choice B rationale
Patient A, diagnosed with emphysema and has an oxygen saturation of 94% on room air, does not necessarily need an increase in oxygen. An oxygen saturation of 94% is within normal limits.
Choice C rationale
Patient B, who is postoperative with a hemoglobin level of 8.2 mg/dL (82 g/L), may require a blood transfusion. A hemoglobin level of 8.2 mg/dL is low, and having packed cells available is a prudent measure.
Choice D rationale
Patient C, newly admitted with a potassium level of 3.8 mEq/L (3.8 mmol/L), has a normal potassium level. Including a banana in the breakfast tray is not a priority.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is ["1.32"]
Explanation
Step 1 is to convert the patient’s weight from pounds to kilograms. There are approximately 2.2046 pounds in 1 kilogram. So, the patient’s weight in kilograms is 132 lb ÷ 2.2046 = 59.87 kg.
Step 2 is to calculate the total dose of lorazepam the patient should receive. The prescribed dose is 44 mcg/kg. So, the total dose in micrograms is 44 mcg/kg × 59.87 kg = 2634.28 mcg.
Step 3 is to convert the total dose from micrograms to milligrams. There are 1000 micrograms in 1 milligram. So, the total dose in milligrams is 2634.28 mcg ÷ 1000 = 2.63428 mg.
Step 4 is to calculate the volume of lorazepam solution to administer. The concentration of the solution is 2 mg/mL. So, the volume in milliliters is 2.63428 mg ÷ 2 mg/mL = 1.31714 mL. Therefore, the nurse should administer approximately 1.32 mL of the lorazepam solution, rounding to the nearest hundredth as required.
Correct Answer is ["A","B","C","D","E","F"]
Explanation
The assessment findings that require immediate follow up by the nurse are: The client has mild subcostal retractions. This could indicate that she is using accessory muscles to breathe, which is a sign of respiratory distress. The client is sitting in an upright position. This is a common position for people who are having difficulty breathing because it allows for maximum expansion of the lungs. Wheezes are noted throughout the lung fields. Wheezing can be a sign of an obstructive process such as asthma. The client is pale. Paleness can be a sign of decreased oxygenation. Her heart rate is 122 beats/minute, which is above the normal range and can indicate that her body is working harder to get oxygen. Her oxygen saturation is 91% on room air. Normal oxygen saturation is generally 95% or higher, so this could indicate that she is not getting enough oxygen.
Whether you are a student looking to ace your exams or a practicing nurse seeking to enhance your expertise , our nursing education contents will empower you with the confidence and competence to make a difference in the lives of patients and become a respected leader in the healthcare field.
Visit Naxlex, invest in your future and unlock endless possibilities with our unparalleled nursing education contents today
Report Wrong Answer on the Current Question
Do you disagree with the answer? If yes, what is your expected answer? Explain.
Kindly be descriptive with the issue you are facing.
