The negative control used in the tests for protein, lipids, sugars, and starch was
Albumin solution
Starch solution
Glucose solution
Olive oil
Distilled water
The Correct Answer is E
Choice A rationale: Albumin solution is not a negative control, but a positive control for the test for protein. Albumin is a type of protein that reacts with the biuret reagent and produces a violet color. A positive control is used to confirm that the test works and gives a positive result when the substance is present³.
Choice B rationale: Starch solution is not a negative control, but a positive control for the test for starch. Starch is a type of carbohydrate that reacts with the iodine solution and produces a blue-black color. A positive control is used to confirm that the test works and gives a positive result when the substance is present³.
Choice C rationale: Glucose solution is not a negative control, but a positive control for the test for sugar. Glucose is a type of sugar that reacts with the Benedict's solution and produces a red-orange color. A positive control is used to confirm that the test works and gives a positive result when the substance is present³.
Choice D rationale: Olive oil is not a negative control, but a positive control for the test for lipids. Olive oil is a type of lipid that reacts with the Sudan III solution and produces a red color. A positive control is used to confirm that the test works and gives a positive result when the substance is present³.
Choice E rationale: Distilled water is a negative control for the tests for protein, lipids, sugars, and starch. Distilled water is a pure solvent that does not contain any of these substances. It does not react with any of the reagents and does not produce any color change. A negative control is used to confirm that there is no response to the reagent or the microorganism used in the test. It is used to set the baseline and verify that the detecting reagent is working properly³.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is A
Explanation
Choice A rationale: A cover slip is correct because a cover slip is a thin, transparent piece of glass or plastic that can be placed over the specimen on the slide. A cover slip protects the specimen from drying out, dust, or damage, and creates a flat surface for viewing under the microscope.
Choice B rationale: Clear paper is incorrect because clear paper is not suitable for covering a wet mount specimen. Clear paper is a type of paper that is transparent or translucent, but it is not thin or flat enough to fit over the specimen on the slide. Clear paper can also interfere with the passage of light or distort the image of the specimen.
Choice C rationale: Transparent tape is incorrect because transparent tape is also not suitable for covering a wet mount specimen. Transparent tape is a type of adhesive tape that is clear or see-through, but it is sticky and can damage the specimen or the slide. Transparent tape can also affect the quality of the image or the focus of the microscope.
Choice D rationale: Another glass slide is incorrect because another glass slide is too thick and heavy to cover a wet mount specimen. Another glass slide is a thin, flat piece of glass or plastic that can be used to place the specimen on, but not over it. Another glass slide can also crush the specimen or block the light source of the microscope.
Correct Answer is A
Explanation
Diffusion is a passive process that does not require energy input from the cell. It is driven by the random motion of molecules that results in a net movement from regions of higher concentration to regions of lower concentration.
Diffusion is one of the ways that substances can cross the cell membrane, such as oxygen, carbon dioxide, and water. Diffusion is important for cellular functions, such as gas exchange, nutrient uptake, and waste removal. Diffusion also helps maintain the homeostasis of the cell by balancing the concentration gradients of different molecules. Therefore, diffusion is the movement of a molecule from an area of higher concentration to an area of lower concentration.
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