A nurse is preparing to administer acetaminophen 15 mg/kg via intermittent IV bolus to a client who weighs 99 lb. The amount available is acetaminophen 1,000 mg/100 mL. How many mL should the nurse administer? (Round the answer to the nearest whole number. Use a leading zero if it applies. Do not use a trailing zero.)
The Correct Answer is ["68"]
To calculate the mL of acetaminophen to administer, follow these steps:
Convert the client's weight from pounds (lb) to kilograms (kg):
Client's weight in kg = Client's weight in lb / 2.2 Client's weight in kg = 99 lb / 2.2 ≈ 45 kg
Determine the total dosage required based on the client's weight:
Total dosage = Client's weight in kg × Dosage (mg/kg) Total dosage = 45 kg × 15 mg/kg = 675 mg
Determine the mL to administer based on the available concentration:
Concentration (mg/mL) = 1,000 mg / 100 mL = 10 mg/mL
Calculate the mL to administer:
mL to administer = Total dosage (mg) / Concentration (mg/mL) mL to administer = 675 mg / 10 mg/mL = 67.5 mL
Round the answer to the nearest whole number:
The nurse should administer 68 mL of acetaminophen
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is ["0.5"]
Explanation
To calculate how many tablets of lisinopril 5 mg the nurse should administer to achieve a 2.5 mg dose, divide the desired dose by the dose per tablet:
Number of tablets = Desired dose / Dose per tablet
Number of tablets = 2.5 mg / 5 mg/tablet
Number of tablets = 0.5 tablets
Correct Answer is ["2.3"]
Explanation
To calculate the amount of morphine (in mL) the nurse should administer, follow these steps:
Step 1: Convert the client's weight from pounds to kilograms. 99 lb / 2.2 lb/kg ≈ 45 kg (rounded to the nearest whole number)
Step 2: Calculate the total dose based on the client's weight. 0.1 mg/kg * 45 kg = 4.5 mg
Step 3: Determine how many mL of the available morphine solution (2 mg/mL) are needed to achieve the prescribed dose. 4.5 mg ÷ 2 mg/mL = 2.25 mL
Rounded to the nearest tenth, the nurse should administer 2.3 mL of morphine.
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