A nurse is performing a Weber test on a client who reports difficulty hearing in his left ear. The client informs the nurse that he can hear the tone louder in his left ear. Which of the following does this result indicate?

The test is inconclusive

The client has conductive hearing loss

The client has normal hearing

The client has sensorineural hearing loss

Answer and Explanation

The Correct Answer is B

Choice A Reason: The test is not inconclusive, but rather positive for conductive hearing loss. The Weber test involves placing a vibrating tuning fork on the center of the forehead and asking the client which ear hears the sound louder. It can help differentiate between conductive and sensorineural hearing loss.

Choice B Reason: This is the correct choice. The client has conductive hearing loss, which is a type of hearing loss that occurs when sound waves are blocked or reduced in the outer or middle ear. It can be caused by earwax, infection, fluid, perforation, or trauma. In conductive hearing loss, the Weber test shows lateralization to the affected ear, meaning the sound is heard louder in that ear.

Choice C Reason: The client does not have normal hearing, but rather conductive hearing loss. In normal hearing, the Weber test shows no lateralization, meaning the sound is heard equally in both ears.

Choice D Reason: The client does not have sensorineural hearing loss, but rather conductive hearing loss. Sensorineural hearing loss is a type of hearing loss that occurs when there is damage to the inner ear or auditory nerve. It can be caused by aging, noise exposure, disease, or drugs. In sensorineural hearing loss, the Weber test shows lateralization to the unaffected ear, meaning the sound is heard louder in that ear.

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Correct Answer is ["B","D","F"]

Explanation

Choice A Reason: Slow even breathing is not a sign of Cushing's Triad, which is a late indicator of increased intracranial pressure (ICP). The breathing pattern may be altered due to brainstem compression, but not necessarily slow or even.

Choice B Reason: This is a correct answer because bradycardia and bounding pulse are part of Cushing's Triad, which reflects an increased vagal tone and decreased cardiac output due to increased ICP.

Choice C Reason: Systolic hypotension with a narrowing pulse pressure is not a sign of Cushing's Triad, which involves an increased systolic blood pressure and a widened pulse pressure due to increased ICP. Hypotension may occur due to shock or hemorrhage, but not as a result of increased ICP.

Choice D Reason: This is a correct answer because irregular respirations are part of Cushing's Triad, which reflects impaired respiratory control due to brainstem compression from increased ICP. The respirations may be Cheyne-Stokes, central neurogenic hyperventilation, apneustic, or ataxic.

Choice E Reason: Tachycardia and bounding pulse are not signs of Cushing's Triad, which involves bradycardia and bounding pulse due to increased ICP. Tachycardia may occur due to pain, anxiety, fever, or hypoxia, but not as a result of increased ICP.

Choice F Reason: This is a correct answer because systolic hypertension with a widening pulse pressure are part of Cushing's Triad, which reflects an increased cerebral perfusion pressure due to increased ICP. The diastolic blood pressure remains stable or decreases, resulting in a widened pulse pressure.

A. Culture B. KOH C. Diascopy D. Wood's

Correct Answer is D

Explanation

Choice A Reason: Culture is not a diagnostic test that uses an ultraviolet light source, but a laboratory test that involves growing microorganisms from a sample of body fluid or tissue. Culture can help identify the type and sensitivity of the infection-causing agent.

Choice B Reason: KOH is not a diagnostic test that uses an ultraviolet light source, but a chemical test that involves applying potassium hydroxide to a sample of skin, hair, or nail. KOH can help diagnose fungal infections by dissolving the keratin and revealing the fungal elements under a microscope.

Choice C Reason: Diascopy is not a diagnostic test that uses an ultraviolet light source, but a physical test that involves applying pressure to a lesion with a glass slide or lens. Diascopy can help differentiate between blanchable and non-blanchable lesions, such as erythema or petechiae.

Choice D Reason: Wood's is a diagnostic test that uses an ultraviolet light source, also known as a Wood's lamp or black light. Wood's can help observe color changes to the skin that are not visible under normal light, such as fluorescence or hypopigmentation. Wood's can help diagnose conditions such as tinea capitis, vitiligo, or erythrasma.

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A nurse is performing a Weber test on a client who reports difficulty hearing in his left ear. The client informs the nurse that he can hear the tone louder in his left ear. Which of the following does this result indicate?

Nursing Test Bank

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