A nurse is administering an intravenous (IV) infusion of 2 g cefotaxime dissolved in 100 mL of isotonic glucose solution to a client. The drop factor of the IV tubing is 15 drops/mL.
If the infusion time is 1 hr, what is the gt/min?
400 gt/min
6 gt/min
25 gt/min
9 gt/min
The Correct Answer is C
The gt/min is 25.
This answer is correct because it is based on a simple formula and calculation. The nurse should use the following formula to calculate the gt/min:
gt/min = (Volume in mL x Drop factor in gt/mL) / Time in min
Plugging in the given values, the nurse should get:
gt/min = (100 mL x 15 gt/mL) / 60 min
gt/min = 25
Therefore, the gt/min is 25.
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Related Questions
Correct Answer is D
Explanation
To find the amount of solution to draw for one dose, you need to calculate the following:
- The body surface area (BSA) of the client in square meters (m²) using the formula: BSA (m²) = √(Height (cm) x Weight (kg) / 3600)
- The dose of allopurinol in milligrams (mg) using the formula: Dose (mg) = BSA (m²) x Prescribed dose
(mg/m²)
- The volume of solution in milliliters (mL) using the formula: Volume (mL) = Dose (mg) / Concentration (mg/mL)
First, use the formula for BSA to find the client's body surface area in square meters:
BSA (m²) = √(Height (cm) x Weight (kg) / 3600)
Since the client's height is 148 cm and weight is 55 kg, plug in these values into the formula:
BSA (m²) = √(148 cm x 55 kg / 3600)
Simplify and solve for the BSA:
BSA (m²) = 1.41 m²
Next, use the formula for dose to find the amount of allopurinol in milligrams:
Dose (mg) = BSA (m²) x Prescribed dose (mg/m²)
Since the client's BSA is 1.41 m² and the prescribed dose is 115 mg/m², plug in these values into the formula:
Dose (mg) = 1.41 m² x 115 mg/m²
Simplify and solve for the dose:
Dose (mg) = 162.15 mg
Then, use the formula for volume to find the amount of solution in milliliters:
Volume (mL) = Dose (mg) / Concentration (mg/mL)
Since the dose is 162.15 mg and the concentration is 25 mg/mL, plug in these values into the formula:
Volume (mL) = 162.15 mg / 25 mg/mL
Simplify and solve for the volume:
Volume (mL) = 6.486 mL
Therefore, the nurse should draw **6.486 mL** of solution for one dose of allopurinol.
Correct Answer is ["B","C","D"]
Explanation
The three components of communication are the sender, the receiver, and the message. The sender is the person who initiates the communication by sending a message. The receiver is the person who receives the message. The message is the information that is being communicated.
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