A nurse in a family health clinic is collecting data as part of a routine physical examination of a client who is about to enter high school. The nurse observes an abnormal lateral curvature of the spine. The nurse should expect the provider to document which of the following disorders?
Scoliosis
Ankylosis
Kyphosis
Lordosis
The Correct Answer is A
A. Scoliosis: Scoliosis is characterized by an abnormal lateral curvature of the spine, commonly detected during routine physical exams in school-aged children and adolescents. This is the correct diagnosis for the described symptom.
B. Ankylosis: Ankylosis refers to joint stiffness or immobility due to fusion of the bones, not a lateral curvature of the spine. It is typically associated with conditions like ankylosing spondylitis and does not describe a spinal curvature.
C. Kyphosis: Kyphosis involves an abnormal forward curvature of the spine, often resulting in a hunchback appearance. It is not the same as a lateral curvature and thus does not fit the description given.
D. Lordosis: Lordosis is characterized by an exaggerated inward curve of the lower spine, commonly referred to as swayback. It does not involve lateral curvature and therefore is not relevant to the described condition.
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Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
A. Supine: Lying on the back can limit lung expansion and is not the best position for a child with respiratory issues. It can contribute to atelectasis and does not facilitate effective breathing.
B. Prone: The prone position can improve oxygenation and ventilation, particularly in severe respiratory distress, but it may not be the most comfortable or practical for all patients, especially in a non-ICU setting.
C. Upright: Sitting upright or in a high Fowler's position is optimal for lung expansion. It facilitates easier breathing and helps the lungs expand more fully, allowing for better oxygenation.
D. Side-lying: Side-lying may be comfortable but does not provide as much benefit for lung expansion as the upright position. It is less effective in promoting maximal lung expansion compared to the upright position.
Correct Answer is ["3.8"]
Explanation
Convert the child’s weight to kg:
22 lb ×1kg/2.2lb = 10 kg
Calculate the daily dose:
1.5 mg/kg/day × 10 kg=15mg/day
Divide the total daily dose by the number of doses per day (every 6 hours):
15mg/day ÷ 4doses/day =3.75mg/dose
Convert the dose to mL using the concentration:
3.75mg × 1 mL/1 mg = 3.75 mL
Round to the nearest tenth:
3.75mL≈ 3.8 mL
Answer: The nurse should administer 3.8 mL per dose.
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