A new patient is admitted to a medical unit with Clostridium difficile (C-diff). Which type of precautions or isolation should the nurse apply for this patient?
Droplet Precautions
Contact Precautions
Airborne Precautions
Neutropenic Precautions
The Correct Answer is B
The correct answer is choice B: Contact Precautions. Clostridium difficile (C-diff) is a bacterium that can cause severe diarrhea and other gastrointestinal problems. It is highly contagious and spreads through contact with contaminated surfaces or objects. Therefore, it is necessary to apply Contact Precautions for patients with C-diff to prevent the transmission of the infection. Contact Precautions involve wearing gloves and gowns when entering the patient's room and disposing of contaminated items properly. Additionally, hand hygiene is critical to preventing the spread of C-diff.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is D
Explanation
A. 2+ Pitting Edema:This refers to moderate pitting edema where the indentation is approximately 4 mm and disappears within 10-15 seconds.
B. 3+ Pitting Edema:This refers to moderately severe pitting edema where the indentation is approximately 6 mm and may last longer than 1 minute but does not remain for as long as 4 minutes.
C. 1+ Non-Pitting Edema:This grade refers to mild pitting edema with a 2 mm indentation that quickly disappears within a few seconds.
D. 4+ Pitting Edema:4+ pitting edema is characterized by a very deep pit (approximately 8 mm) that may last 2-5 minutes or more. This matches the scenario where the pit is 8 mm deep and remains for 4 minutes.
Correct Answer is ["725"]
Explanation
Intake = IV fluid + antibiotic
From 0700-0900 (2 hours), the patient received 100 mL/hr of IV fluid: 100 mL/hr x 2 hours = 200 mL
From 1000-1030 (0.5 hours), the patient received Kefzol 1 g in 25 mL of D5W over 30 minutes:
25 mL
From 1030-1530 (5 hours), the patient received 100 mL/hr of IV fluid: 100 mL/hr x 5 hours = 500 mL
Total intake from 0700-1530 = 200 mL + 25 mL + 500 mL = 725 mL. Therefore, the patient's intake from 0700 to 1530 was 725 mL.
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