A client with dehydration is prescribed a potassium chloride infusion at 10 mEq/hr. Potassium chloride 80 mEq is mixed with 1 liter of normal saline. The nurse should regulate the infusion pump to deliver how many mL/hour? (Enter numeric value only. If rounding is required, round to the nearest whole number.)
The Correct Answer is ["125"]
To calculate the infusion rate in mL/hour, we'll use the following formula:
Infusion Rate (mL/hr) = Desired Dose (mEq/hr) / Concentration of Potassium Chloride (mEq/mL)
1. Calculate the concentration of potassium chloride:
Concentration = 80 mEq / 1000 mL = 0.08 mEq/mL
2. Plug in the values:
Infusion Rate (mL/hr) = 10 mEq/hr / 0.08 mEq/mL
3. Calculate:
Infusion Rate (mL/hr) = 125 mL/hr
Therefore, the nurse should regulate the infusion pump to deliver 125 mL/hour.
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Related Questions
Correct Answer is ["56"]
Explanation
Answer: 56 gtt/min.
Rationale:
To calculate the infusion rate in gtt/min, we'll use the following formula:
Infusion Rate (gtt/min) = Volume (mL) / Time (min) x Drop Factor (gtt/mL)
1. Convert volume to mL:
2 liters = 2000 mL
2. Convert time to minutes:
12 hours = 12 x 60 = 720 minutes
3. Plug in the values:
Infusion Rate (gtt/min) = 2000 mL / 720 min x 20 gtt/mL
4. Calculate:
Infusion Rate (gtt/min) ≈ 55.56 gtt/min
5. Round to the nearest whole number:
Infusion Rate (gtt/min) ≈ 56 gtt/min
Therefore, the nurse should regulate the infusion to 56 gtt/min.
Correct Answer is ["120"]
Explanation
The healthcare provider prescribes a continuous infusion of labetalol at 2 mg/minute.
Labetalol HCI Injection USP 200 mg in 200 mL of 5% Dextrose Injection, USP, is delivered to the unit. This means that for every mL of the solution, there is 1 mg of labetalol (200 mg / 200 mL = 1 mg/mL).
To administer a dose of 2 mg/minute, the nurse should program the infusion pump to deliver 120 mL/hour (2 mg/minute × 60 minutes/hour = 120 mg/hour; 120 mg/hour ÷ 1 mg/mL = 120 mL/hour).
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