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A client with an acute stroke must receive Alteplase 0.9 mg/kg. The client weighs 220 pounds. How should the client receive? (Round to the nearest whole number, do not use trailing zeros)

Answer and Explanation

The Correct Answer is ["90"]

Given:

Ordered dose of Alteplase: 0.9 mg/kg

Client weight: 220 pounds

Step 1: Convert the client's weight from pounds to kilograms:

1 pound (lb) = 0.453592 kilograms (kg)

Client weight in kg = 220 lbs x 0.453592 kg/lb = 99.76824 kg

Step 2: Calculate the total dose of Alteplase:

Total dose (mg) = Ordered dose (mg/kg) xClient weight (kg)

Total dose (mg) = 0.9 mg/kg x 99.76824 kg

Total dose (mg) = 89.801416 mg

Step 3: Round to the nearest whole number:

Total dose (mg) ≈ 90 mg

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Correct Answer is A

Explanation

A) Use the 3-second markers to count the number of QRS complexes in 6 seconds and multiply by 10:
The 3-second markers on the ECG strip represent a fixed time interval. By counting the number of QRS complexes in the 6-second interval (i.e., two 3-second markers), you can estimate the heart rate by multiplying the number of QRS complexes by 10. This method is quick and effective for calculating heart rate in an emergency setting, such as in arrhythmias or when time is of the essence.

B) Print a 1-minute ECG strip and count the number of QRS complexes:
While this is another way to assess the heart rate, it is not a quick method, especially in emergency situations. It is more time-consuming because it involves printing out a full strip (or ensuring you have enough data to calculate a full minute). This approach may be useful for detailed analysis but is not optimal for quickly estimating the ventricular rhythm.

C) Calculate the number of small squares between one QRS complex and the next one and divide by 1500:
This method is more complex and is used for calculating the heart rate with a more precise ECG reading. It requires counting the number of small squares between two QRS complexes and dividing by 1500 (the number of small squares in one minute). This method is accurate but not the fastest option for quickly estimating the heart rate during an emergency.

D) Count the number of large squares in the R-R interval and divide by 300:
counting the number of large squares between two R-R intervals and dividing by 300, you get the heart rate. However, this method is less commonly used in emergency situations because it requires more time and may not be as immediate as using the 3-second markers. It is more applicable when doing a detailed analysis of the rhythm.

A. if there is a QRS complex after each p wave B. the rate using only a 3- second strip C. the duration of the u waves D. if the p waves are present E. If the P-P and R-R distances are equal

Correct Answer is ["A","D","E"]

Explanation

A) If there is a QRS complex after each P wave:
This is an important consideration when identifying a cardiac rhythm. The P wave represents atrial depolarization, and the QRS complex represents ventricular depolarization. In a normal sinus rhythm, every P wave is followed by a QRS complex, which confirms that the impulse originating in the SA node is being conducted properly through the atrioventricular (AV) node and into the ventricles. The presence of a QRS after every P wave helps confirm normal conduction and rhythm.

B) The rate using only a 3-second strip:
While the heart rate is an essential part of the rhythm assessment, using only a 3-second strip is not the most accurate method for determining the rate. Typically, a 6-second strip is used to estimate the rate, multiplying the number of R-R intervals by 10 to obtain the heart rate. A 3-second strip can be used for quick estimates but may lead to inaccurate calculations of the heart rate.

C) The duration of the U waves:
The U wave is often a normal variant seen in the ECG and is not always present. If it is visible, its duration is typically not a primary focus in rhythm interpretation unless there are concerns about electrolyte imbalances, such as hypokalemia. The U wave is not a core factor to consider when identifying the overall rhythm.

D) If the P waves are present:
The presence of P waves is important for identifying the rhythm, particularly when differentiating between sinus rhythms (normal) and non-sinus rhythms (such as atrial arrhythmias). In normal sinus rhythm, P waves should be present, reflecting atrial depolarization initiated by the SA node. The absence of P waves can indicate atrial fibrillation, atrial flutter, or other arrhythmias.

E) If the P-P and R-R distances are equal:
This is crucial in identifying a regular rhythm. The P-P interval refers to the distance between successive P waves (atrial depolarization), and the R-R interval refers to the distance between successive R waves (ventricular depolarization). In normal sinus rhythm or regular rhythms, both the P-P and R-R intervals should be equal, indicating that the atrial and ventricular rhythms are consistent. If they are unequal, it suggests an irregular rhythm (e.g., atrial fibrillation).

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A client with an acute stroke must receive Alteplase 0.9 mg/kg. The client weighs 220 pounds. How should the client receive? (Round to the nearest whole number, do not use trailing zeros)

Nursing Test Bank

Naxlex Comprehensive Predictor Exams

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Explanation

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Explanation

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