A client receives a prescription for loratadine suspension 10 mg by mouth once a day. The bottle is labeled "Loratadine for Oral Suspension, USP 5 mg per 5 mL." How many teaspoons should the nurse instruct the client to take? (Enter numerical value only.)
The Correct Answer is ["2"]
To find the answer, we can use the following steps:
- Calculate the volume of loratadine suspension in mL by dividing the dose in mg by the concentration in mg/mL
- Convert the volume in mL to teaspoons by multiplying by 0.2
- Round the result to the nearest whole number
Using these steps, we get:
- (volume in mL) = (10) / (5 / 5) = 10 mL
- (volume in teaspoons) = (10) x (0.2) = 2 teaspoons
- (rounded volume in teaspoons) = 2 teaspoons
Therefore, the nurse should instruct the client to take 2 teaspoons of loratadine suspension.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is ["1 mL"]
Explanation
The correct answer is 1 mL. To find the answer, we can use the following steps:
- Convert the client's weight from pounds to kilograms by dividing by 2.2
- Multiply the weight in kilograms by the dosage in mg/kg
- Divide the dose in mg by the concentration in mg/mL
- Round the result to the nearest whole number
Using these steps, we get:
- (weight in kg) = (176) / (2.2) = 80 kg
- (dose in mg) = (0.05) x (80) = 4 mg
- (volume in mL) = (4) / (4) = 1 mL
- (rounded volume in mL) = 1 mL
Therefore, the nurse should administer 1 mL of lorazepam from the vial to the client.
Correct Answer is ["10 mL"]
Explanation
To find the answer, we can use the following steps:
- Convert the child's weight from pounds to kilograms by dividing by 2.2
- Calculate the volume of amoxicillin suspension in mL by dividing the dose in mg by the concentration in mg/mL
- Round the result to the nearest whole number
Using these steps, we get:
- (weight in kg) = (88) / (2.2) = 40 kg
- (volume in mL) = (500) / (250 / 5) = 10 mL
- (rounded volume in mL) = 10 mL
Therefore, the nurse should administer 10 mL of amoxicillin suspension to the child.
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