The healthcare provider prescribes a hydration infusion of normal saline to run over 3 hours at 30 mL/kg for a client who is dehydrated and weighs 70 kg. The nurse should program the infusion pump to deliver how many mL/hour? (Enter numeric value only.)
The Correct Answer is ["700 mL\/hour"]
To find the answer, we can use the following steps:
- Calculate the total volume of normal saline in mL by multiplying the weight in kg by the dosage in mL/kg
- Divide the total volume of normal saline in mL by the number of hours to get the rate in mL/hour
- Round the result to the nearest whole number
Using these steps, we get:
- (total volume in mL) = (30) x (70) = 2100 mL
- (rate in mL/hour) = (2100) / (3) = 700 mL/hour
- (rounded rate in mL/hour) = 700 mL/hour
Therefore, the nurse should program the infusion pump to deliver 700 mL/hour of normal saline.
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Related Questions
Correct Answer is ["17 mL\/hour"]
Explanation
The correct answer is 17 mL/hour. To find the answer, we can use the following formula:
(mL/hour) = (units/hour) x (mL per unit)
Substituting the given values, we get:
(mL/hour) = (1,400) x (250 / 20,000)
Simplifying, we get:
(mL/hour) = (1,400) x (0.0125)
(mL/hour) = 17.5
(rounded mL/hour) = 17
Therefore, the nurse should program the infusion pump to deliver 17 mL/hour of heparin in dextrose 5% in water.
Correct Answer is ["9000"]
Explanation
To find the answer, we can use the following steps:
- Convert the client's weight from pounds to kilograms by dividing by 2.2
- Multiply the weight in kilograms by the dosage in units/kg
- Round the result to the nearest whole number
Using these steps, we get:
- (weight in kg) = (198) / (2.2) = 90 kg
- (dose in units) = (100) x (90) = 9000 units
- (rounded dose in units) = 9000 units
Therefore, the nurse should administer 9000 units of IV Heparin to the client.
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